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tmagloire1
 one year ago
What is the area of the largest rectangle with lower base on the xaxis and upper vertices on the curve y = 3 − x^2?
tmagloire1
 one year ago
What is the area of the largest rectangle with lower base on the xaxis and upper vertices on the curve y = 3 − x^2?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay here is the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Area = x * y We need to find our X, because the height is a function of X. You can divide this problem into 2 rectangles, each one to both sides of the y axis, and the "big" rectangle will be the sum of both. so, the rectangle will have area = x * (12  x^2) you have to maximize it, so we differentiate it: d(area)/dx = 123*x^2 = 0. then x = 2 the area would be 2*(124) = 16 lets see if its maximum or minimum... if we choose x = 0, we would get a height o 12, but an area of 0, so its a maximum (without doing any derivative tests :D ) So the area of both rectangles would be 32 units squared

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0._. that wasn't even my problem. where did you get those numbers from

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0but ill try this way and see what i get

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0they used a different curve, but the process seems good enough.

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0i got 4! thanks for the process
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