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anonymous

  • one year ago

How to factor 10x2-80 Pls list steps

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  1. anonymous
    • one year ago
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    \[10x^{2} - 80\]

  2. anonymous
    • one year ago
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    well do you know what 10^2 is

  3. anonymous
    • one year ago
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    well its 10 x 10 = 100

  4. anonymous
    • one year ago
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    100

  5. anonymous
    • one year ago
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    Yea lol

  6. anonymous
    • one year ago
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    so now the problem is 100 - 80

  7. anonymous
    • one year ago
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    but thats not factoring

  8. anonymous
    • one year ago
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    ok it's 20.

  9. anonymous
    • one year ago
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    ohh

  10. anonymous
    • one year ago
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    https://www.symbolab.com/solver/algebra-calculator/10%5E%7B2%7D-80/?origin=button this may help if not im sorry

  11. anonymous
    • one year ago
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    Its 10(x^2-8)

  12. anonymous
    • one year ago
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    Its alright :) thanks

  13. anonymous
    • one year ago
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    ok i can help with that if you still need help

  14. anonymous
    • one year ago
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    let me give some a try, give me a min

  15. anonymous
    • one year ago
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    @chinadayyy 16x^2-4

  16. anonymous
    • one year ago
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    ok is this factoring again?

  17. anonymous
    • one year ago
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    yup

  18. anonymous
    • one year ago
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    @haleyelizabeth2017

  19. happy_to_help
    • one year ago
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    \[16(x^{2}-4)\] Step one:Use distributive property 16 times x to the power of 2=16x^2 16 times 4=64 16x^2-64

  20. anonymous
    • one year ago
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    Eli

  21. anonymous
    • one year ago
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    So for 16x^2-4 I got (4x-2) (4x+2)

  22. haleyelizabeth2017
    • one year ago
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    That is one way to do it

  23. haleyelizabeth2017
    • one year ago
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    But, that's not the simplest form.

  24. anonymous
    • one year ago
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    for 4x^2-25 i got (2x-5) (2x+5)

  25. anonymous
    • one year ago
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    It isn't?

  26. haleyelizabeth2017
    • one year ago
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    Yes :)

  27. haleyelizabeth2017
    • one year ago
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    and no

  28. anonymous
    • one year ago
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    Explain ? pls :)

  29. haleyelizabeth2017
    • one year ago
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    For \(16x^2-4\) the simplest form would be 4(2x-1)(2x+1)

  30. haleyelizabeth2017
    • one year ago
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    because you would get \(4(4x^2-1)\) which \(4x^2-1\) turns into (2x-1)(2x+1)

  31. haleyelizabeth2017
    • one year ago
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    So, then you move the four back and get 4(2x-1)(2x+1)

  32. anonymous
    • one year ago
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    OHH I see it..

  33. haleyelizabeth2017
    • one year ago
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    :)

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