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tmagloire1

  • one year ago

ap calc ab last problem i need help with ! http://prntscr.com/8o5kna

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  1. amistre64
    • one year ago
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    what did you try?

  2. tmagloire1
    • one year ago
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    I graphed them and this is what i got : http://prntscr.com/8o5mj6

  3. tmagloire1
    • one year ago
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    but the two graphs under those constraints never meet

  4. amistre64
    • one year ago
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    youre graph is good, it isnt pieced tho ..

  5. amistre64
    • one year ago
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    |dw:1444081637607:dw|

  6. tmagloire1
    • one year ago
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    how can it be 1 if on the second equation x<0

  7. tmagloire1
    • one year ago
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    @amistre64

  8. amistre64
    • one year ago
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    -2 <= x <= 0 x > 0

  9. amistre64
    • one year ago
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    the graphs touch, they are continuous along -2 to infinity simply becuase they are defined for all real values.

  10. amistre64
    • one year ago
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    the top is defined at x=0, the bottom is arbitrarily close to x=0

  11. tmagloire1
    • one year ago
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    so we would count 0 as a maximum then?

  12. amistre64
    • one year ago
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    when x=0, what is our value of the function?

  13. tmagloire1
    • one year ago
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    oops i meant 1!

  14. amistre64
    • one year ago
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    at x=0, the max is obtianed, and its value is 1

  15. tmagloire1
    • one year ago
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    A bit confused so the max is 0 of my choices, but the value is 1?

  16. amistre64
    • one year ago
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    the max is when x=0 ... it is not asking you for the value of x that gets us a max value ... it is asking for the max value itself. f(0) = 1

  17. tmagloire1
    • one year ago
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    ohh ok i didn't ge the whole value part. alright thanks for explaining it!

  18. amistre64
    • one year ago
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    good luck

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is replying to Can someone tell me what button the professor is hitting...

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