anonymous
  • anonymous
When I have something like: Al(OH)3 would I set it up like this: 26.982(15.999+1.008)*3?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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hwyl
  • hwyl
what are you trying to do?
anonymous
  • anonymous
mole to grams conversions the question is: How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3
hwyl
  • hwyl
ah

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hwyl
  • hwyl
how many moles of \(\sf Al(OH)_3 \) do you have?
anonymous
  • anonymous
thats the question; it only gave grams for me to find that.
hwyl
  • hwyl
you only have one mole
hwyl
  • hwyl
if you do not see a number before the name of the compound or molecule then it means there is only one mole.
hwyl
  • hwyl
\(\sf \huge x~ mole_{Al(OH)_3} \times \frac{grams_{Al(OH)_3}}{1 ~ mole_{Al(OH)_3}} = \)
hwyl
  • hwyl
do you see how the mole unit for a particular thing is canceled out algebraically?
hwyl
  • hwyl
\(\large a \times \huge \frac{b}{a} = b\)
anonymous
  • anonymous
yeah I see where it would be cancelled out. I just need to know how to find the molecular weight of the aluminum hydroxide.
hwyl
  • hwyl
whatever unit you're trying to convert out of, you need to divide by itself
hwyl
  • hwyl
molecular weight follows the conservation of mass so if you see Al it means there is 1 Al in there if you see \(\sf (OH)_3\) it means that there are 3 O's and 3 H's; the subscripts tell you how many there are for whatever each element that is enclosed in parenthesis
hwyl
  • hwyl
usually when there's 1, we do not write it out. it is just like saying a mole of something - it is implicit that the word "a" denotes 1
hwyl
  • hwyl
you're going to add all the weights of each elements in that molecule/compound
hwyl
  • hwyl
\(\sf \large Al(OH)_3 = [1 \times (weight_{Al})] + [3 \times (weight_{O}+weight_{H})] \)
hwyl
  • hwyl
get it?
anonymous
  • anonymous
so the answer is 78.003 correct?
hwyl
  • hwyl
I don't know the individual atomic mass units of each elements, that is something you need to reference to a periodic table.
anonymous
  • anonymous
its in the top
hwyl
  • hwyl
then start adding and multiplying
anonymous
  • anonymous
okay well thank you so much for you're help!!
anonymous
  • anonymous
@hwyl what about when it says: Ca3(PO3)2
hwyl
  • hwyl
Ca: \(3 \times \sf Ca \) P: \(2 \times \sf P \) O: \(2 \times 3 \sf ~ O \)

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