When I have something like: Al(OH)3 would I set it up like this: 26.982(15.999+1.008)*3?

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When I have something like: Al(OH)3 would I set it up like this: 26.982(15.999+1.008)*3?

Chemistry
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what are you trying to do?
mole to grams conversions the question is: How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3
ah

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how many moles of \(\sf Al(OH)_3 \) do you have?
thats the question; it only gave grams for me to find that.
you only have one mole
if you do not see a number before the name of the compound or molecule then it means there is only one mole.
\(\sf \huge x~ mole_{Al(OH)_3} \times \frac{grams_{Al(OH)_3}}{1 ~ mole_{Al(OH)_3}} = \)
do you see how the mole unit for a particular thing is canceled out algebraically?
\(\large a \times \huge \frac{b}{a} = b\)
yeah I see where it would be cancelled out. I just need to know how to find the molecular weight of the aluminum hydroxide.
whatever unit you're trying to convert out of, you need to divide by itself
molecular weight follows the conservation of mass so if you see Al it means there is 1 Al in there if you see \(\sf (OH)_3\) it means that there are 3 O's and 3 H's; the subscripts tell you how many there are for whatever each element that is enclosed in parenthesis
usually when there's 1, we do not write it out. it is just like saying a mole of something - it is implicit that the word "a" denotes 1
you're going to add all the weights of each elements in that molecule/compound
\(\sf \large Al(OH)_3 = [1 \times (weight_{Al})] + [3 \times (weight_{O}+weight_{H})] \)
get it?
so the answer is 78.003 correct?
I don't know the individual atomic mass units of each elements, that is something you need to reference to a periodic table.
its in the top
then start adding and multiplying
okay well thank you so much for you're help!!
@hwyl what about when it says: Ca3(PO3)2
Ca: \(3 \times \sf Ca \) P: \(2 \times \sf P \) O: \(2 \times 3 \sf ~ O \)

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