A circle is centered at (5, −9) and has a radius of 12. Which of the following is the equation for this circle? (x-5)^2+(y+9)^2=12 (x-5)^2+(y+9)^2=144 (x+5)^2+(y-9)^2=144 (x+5)^2+(y-9)^2=12

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A circle is centered at (5, −9) and has a radius of 12. Which of the following is the equation for this circle? (x-5)^2+(y+9)^2=12 (x-5)^2+(y+9)^2=144 (x+5)^2+(y-9)^2=144 (x+5)^2+(y-9)^2=12

Mathematics
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The equation of this circle is (x-h)^2 + (y-k)^2= r^2 Plug the values in and boom
im still confused ): ?? /: @willet
Okay, in this case, 5 is h and -9 is k and 12 is r

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If you input those value into that equation and simplify, you should get your answer
so then the answer would be A? @Ryan361
Well, you have r^2 so it would be 12^2 which is 144
other than that you are right
actually i wrote the question wrong. its D
I meant i wrote the answers wrong
i corrected them. so my answer is D ? @Ryan361
I'm getting B
But the 5 isnt a negative ... @Ryan361 only the 9 is
The equation you put the numbers into makes it negative
(x-h)^2 + (y-k)^2= r^2 It's "x-h" h is 5. so, x-5
ohh ok thank you!!! (((((:::: @Ryan361
You're welcome
can you help me with one more ? @Ryan361
You just gotta be careful with signs, it's really easy to accidentally do make a mistake
Yea, I can try depends on what it is
What step is needed when constructing a circle circumscribed about a triangle? (1 point) Select one: a. Construct the angle bisectors of each angle in the triangle. b. Construct the perpendicular bisectors of each side of the triangle. c. Construct the midpoints of each side of the triangle. d. Construct the altitude of each angle in the triangle. @Ryan361
I'm pretty sure it's B
http://www.mathsisfun.com/geometry/construct-trianglecircum.html
yes i agree thankssss @Ryan361
Welcome

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