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anonymous

  • one year ago

Write the product as a trinomial (x+2)(x+4) A. X^2+8X+8 B. x^2+8X+6 C. x^2+6 D. X^2+6X+8

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  1. jim_thompson5910
    • one year ago
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    I like to use the box method http://www.purplemath.com/index.htm

  2. jim_thompson5910
    • one year ago
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    |dw:1444087405771:dw|

  3. jim_thompson5910
    • one year ago
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    |dw:1444087426523:dw|

  4. jim_thompson5910
    • one year ago
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    |dw:1444087444357:dw|

  5. anonymous
    • one year ago
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    Ive never heard of box method

  6. jim_thompson5910
    • one year ago
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    |dw:1444087465794:dw|

  7. jim_thompson5910
    • one year ago
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    do you see how I got this far?

  8. anonymous
    • one year ago
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    yes i do see that

  9. jim_thompson5910
    • one year ago
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    ok now we fill out the boxes

  10. jim_thompson5910
    • one year ago
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    we do that by multiplying the stuff on the outside example x times x = x^2 |dw:1444087609845:dw|

  11. anonymous
    • one year ago
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    X^2?

  12. jim_thompson5910
    • one year ago
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    x times 2 = 2x |dw:1444087639360:dw|

  13. jim_thompson5910
    • one year ago
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    do you see how I'm filling out the boxes?

  14. anonymous
    • one year ago
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    yes 4x in the bottom box on left?

  15. anonymous
    • one year ago
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    then 4x2=8

  16. jim_thompson5910
    • one year ago
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    very good |dw:1444087720298:dw| and bottom right?

  17. jim_thompson5910
    • one year ago
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    yes, good |dw:1444087746191:dw|

  18. jim_thompson5910
    • one year ago
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    now we add up all the 4 terms inside the boxes we combine any like terms if they exist, in this case, they do (4x+2x = 6x) so \[\Large x^2 + 2x+4x+8 = x^2 + 6x + 8\]

  19. jim_thompson5910
    • one year ago
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    in the end, \[\Large (x+2)(x+4) = x^2 + 6x + 8\]

  20. YoloShroom
    • one year ago
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    Foil is also really nice.

  21. anonymous
    • one year ago
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    (2x)(4x)=x^2+14?

  22. YoloShroom
    • one year ago
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    If you mean 2x times 4x it's 8x^2 ^_^

  23. anonymous
    • one year ago
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    honest im just lost on that part so i dont know

  24. jim_thompson5910
    • one year ago
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    @YoloShroom FOIL is good but it's restricted. You can only use it if you are multiplying 2 binomials. The box method allows you to multiply any two algebraic expressions (they don't have to be binomials)

  25. YoloShroom
    • one year ago
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    On this problem, or a part of the problem ? Because i can clarify using a different method from what Jim used

  26. YoloShroom
    • one year ago
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    True, It gets more difficult later on if you use foil, but i think it's easier to understand earlier on dont you?

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