anonymous
  • anonymous
Write the product as a trinomial (x+2)(x+4) A. X^2+8X+8 B. x^2+8X+6 C. x^2+6 D. X^2+6X+8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jim_thompson5910
  • jim_thompson5910
I like to use the box method http://www.purplemath.com/index.htm
jim_thompson5910
  • jim_thompson5910
|dw:1444087405771:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1444087426523:dw|

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jim_thompson5910
  • jim_thompson5910
|dw:1444087444357:dw|
anonymous
  • anonymous
Ive never heard of box method
jim_thompson5910
  • jim_thompson5910
|dw:1444087465794:dw|
jim_thompson5910
  • jim_thompson5910
do you see how I got this far?
anonymous
  • anonymous
yes i do see that
jim_thompson5910
  • jim_thompson5910
ok now we fill out the boxes
jim_thompson5910
  • jim_thompson5910
we do that by multiplying the stuff on the outside example x times x = x^2 |dw:1444087609845:dw|
anonymous
  • anonymous
X^2?
jim_thompson5910
  • jim_thompson5910
x times 2 = 2x |dw:1444087639360:dw|
jim_thompson5910
  • jim_thompson5910
do you see how I'm filling out the boxes?
anonymous
  • anonymous
yes 4x in the bottom box on left?
anonymous
  • anonymous
then 4x2=8
jim_thompson5910
  • jim_thompson5910
very good |dw:1444087720298:dw| and bottom right?
jim_thompson5910
  • jim_thompson5910
yes, good |dw:1444087746191:dw|
jim_thompson5910
  • jim_thompson5910
now we add up all the 4 terms inside the boxes we combine any like terms if they exist, in this case, they do (4x+2x = 6x) so \[\Large x^2 + 2x+4x+8 = x^2 + 6x + 8\]
jim_thompson5910
  • jim_thompson5910
in the end, \[\Large (x+2)(x+4) = x^2 + 6x + 8\]
YoloShroom
  • YoloShroom
Foil is also really nice.
anonymous
  • anonymous
(2x)(4x)=x^2+14?
YoloShroom
  • YoloShroom
If you mean 2x times 4x it's 8x^2 ^_^
anonymous
  • anonymous
honest im just lost on that part so i dont know
jim_thompson5910
  • jim_thompson5910
@YoloShroom FOIL is good but it's restricted. You can only use it if you are multiplying 2 binomials. The box method allows you to multiply any two algebraic expressions (they don't have to be binomials)
YoloShroom
  • YoloShroom
On this problem, or a part of the problem ? Because i can clarify using a different method from what Jim used
YoloShroom
  • YoloShroom
True, It gets more difficult later on if you use foil, but i think it's easier to understand earlier on dont you?

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