Write the product as a trinomial (x+2)(x+4) A. X^2+8X+8 B. x^2+8X+6 C. x^2+6 D. X^2+6X+8

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Write the product as a trinomial (x+2)(x+4) A. X^2+8X+8 B. x^2+8X+6 C. x^2+6 D. X^2+6X+8

Mathematics
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I like to use the box method http://www.purplemath.com/index.htm
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Other answers:

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Ive never heard of box method
|dw:1444087465794:dw|
do you see how I got this far?
yes i do see that
ok now we fill out the boxes
we do that by multiplying the stuff on the outside example x times x = x^2 |dw:1444087609845:dw|
X^2?
x times 2 = 2x |dw:1444087639360:dw|
do you see how I'm filling out the boxes?
yes 4x in the bottom box on left?
then 4x2=8
very good |dw:1444087720298:dw| and bottom right?
yes, good |dw:1444087746191:dw|
now we add up all the 4 terms inside the boxes we combine any like terms if they exist, in this case, they do (4x+2x = 6x) so \[\Large x^2 + 2x+4x+8 = x^2 + 6x + 8\]
in the end, \[\Large (x+2)(x+4) = x^2 + 6x + 8\]
Foil is also really nice.
(2x)(4x)=x^2+14?
If you mean 2x times 4x it's 8x^2 ^_^
honest im just lost on that part so i dont know
@YoloShroom FOIL is good but it's restricted. You can only use it if you are multiplying 2 binomials. The box method allows you to multiply any two algebraic expressions (they don't have to be binomials)
On this problem, or a part of the problem ? Because i can clarify using a different method from what Jim used
True, It gets more difficult later on if you use foil, but i think it's easier to understand earlier on dont you?

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