## hpfan101 one year ago How to find the horizontal and vertical asymptote of the function: $g(x)=\frac{ 2 }{ x^2+5 }$ using limits?

1. anonymous

well... the vertical asymptotes occur when the denominator zeros out so.... at what values of "x" does the denominator zeros out that is $$\bf x^2+5=0\implies x=?$$

2. anonymous

hmmm ohh.. using limits... hmm so much for the appending there

3. hpfan101

There's no value of x that'd make the denominator zero.

4. hpfan101

But I think I figured this one out.

5. hpfan101

Thanks anyways!