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hpfan101

  • one year ago

How to find the horizontal and vertical asymptote of the function: \[g(x)=\frac{ 2 }{ x^2+5 }\] using limits?

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  1. jdoe0001
    • one year ago
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    well... the vertical asymptotes occur when the denominator zeros out so.... at what values of "x" does the denominator zeros out that is \(\bf x^2+5=0\implies x=?\)

  2. jdoe0001
    • one year ago
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    hmmm ohh.. using limits... hmm so much for the appending there

  3. hpfan101
    • one year ago
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    There's no value of x that'd make the denominator zero.

  4. hpfan101
    • one year ago
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    But I think I figured this one out.

  5. hpfan101
    • one year ago
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    Thanks anyways!

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