anonymous
  • anonymous
ILL GIVE OUT A MEDAL !! PLEASE HELP !!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
A.40 B. 60 C.20 D.120
YoloShroom
  • YoloShroom
alright, lemme take a look ;)

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anonymous
  • anonymous
@YoloShroom Alright :) i have other questions too if u mind helping will be great! :D
YoloShroom
  • YoloShroom
Damn it, didnt realize this was geometry... Sorry im real bad at it XD but let me see if @jdoe0001 or @JosiahG can help you out... If you have any other non geometry questions feel free to msg me them
anonymous
  • anonymous
jdoe0001
  • jdoe0001
http://www.mathwarehouse.com/geometry/circle/images/power-of-point/far-arc-near-arc-formula-picture-small.png <-- any ideas what S is?
ChantySquirrel1129**
  • ChantySquirrel1129**
Geometry right?
ChantySquirrel1129**
  • ChantySquirrel1129**
I hated geoometry....xD ask iambatman c:
ChantySquirrel1129**
  • ChantySquirrel1129**
jdoe may halp c:
jdoe0001
  • jdoe0001
well, check the "far arc, near arc" theorem closely, should be simple ebough
anonymous
  • anonymous
yea thanks or whatever @ChantySquirrel1129**
anonymous
  • anonymous
@jdoe0001 so i subtract 80 from 40 ? then divide by 2 ?
ChantySquirrel1129**
  • ChantySquirrel1129**
Rude xD
anonymous
  • anonymous
It looks like you answered your own question :)
ChantySquirrel1129**
  • ChantySquirrel1129**
At least I tried to help, you ungrateful little brat.
ChantySquirrel1129**
  • ChantySquirrel1129**
c:
anonymous
  • anonymous
You could also use the process of elimination and see that 20ยบ would be the only possible answer.
anonymous
  • anonymous
@ChantySquirrel1129** u help me ? LOL where ?!
ChantySquirrel1129**
  • ChantySquirrel1129**
I looked at your question and tried to help, retard....Other people didn't...
anonymous
  • anonymous
Is your question answered or not? This isn't the place to debate.
anonymous
  • anonymous
the retard is u . you clearly didnt help me solve the problem u suggested people to help me . go away .
anonymous
  • anonymous
@JosiahG thank you :)
ChantySquirrel1129**
  • ChantySquirrel1129**
c:

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