Find limit as x approaches -1

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my guess is that for a first step, get rid of that compound fraction
okay could you help me with that?

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sure
im betting they want \(x\to 0\)
would make more sense
no it's as \[\lim_{x \rightarrow -1}\]
then without doing a ton of work, you can pretty much forget about a limit existing the denominator of \(\frac{1}{\sqrt{x+1}}\) goes to zero and the numerator does not, so you are not going to have a limit forget i mentioned the algebra, although that is usually a good first step
okay I thought the question was really weird so I put nonexistent as the limit before and just wanted to see if I had done something wrong. Thanks so much!!
yw
btw i guess it is worth mentioning that the domain of this beast is \((-1,\infty)\) so you cannot take the limit in any case a limit is two sided and you cannot approach \(-1\) from the left
ok that is wrong, because the domain excludes zero as well
but the above is still true
yeah I graphed it and it stopped at -1 and only continued onto the right which is why I assumed it was nonexistent

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