cassieforlife5 one year ago Find limit as x approaches -1

1. cassieforlife5

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2. anonymous

my guess is that for a first step, get rid of that compound fraction

3. cassieforlife5

okay could you help me with that?

4. anonymous

sure

5. Zarkon

im betting they want $$x\to 0$$

6. anonymous

would make more sense

7. cassieforlife5

no it's as $\lim_{x \rightarrow -1}$

8. anonymous

then without doing a ton of work, you can pretty much forget about a limit existing the denominator of $$\frac{1}{\sqrt{x+1}}$$ goes to zero and the numerator does not, so you are not going to have a limit forget i mentioned the algebra, although that is usually a good first step

9. cassieforlife5

okay I thought the question was really weird so I put nonexistent as the limit before and just wanted to see if I had done something wrong. Thanks so much!!

10. anonymous

yw

11. anonymous

btw i guess it is worth mentioning that the domain of this beast is $$(-1,\infty)$$ so you cannot take the limit in any case a limit is two sided and you cannot approach $$-1$$ from the left

12. anonymous

ok that is wrong, because the domain excludes zero as well

13. anonymous

but the above is still true

14. cassieforlife5

yeah I graphed it and it stopped at -1 and only continued onto the right which is why I assumed it was nonexistent