cassieforlife5
  • cassieforlife5
Find limit as x approaches -1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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cassieforlife5
  • cassieforlife5
|dw:1444091846364:dw|
anonymous
  • anonymous
my guess is that for a first step, get rid of that compound fraction
cassieforlife5
  • cassieforlife5
okay could you help me with that?

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anonymous
  • anonymous
sure
Zarkon
  • Zarkon
im betting they want \(x\to 0\)
anonymous
  • anonymous
would make more sense
cassieforlife5
  • cassieforlife5
no it's as \[\lim_{x \rightarrow -1}\]
anonymous
  • anonymous
then without doing a ton of work, you can pretty much forget about a limit existing the denominator of \(\frac{1}{\sqrt{x+1}}\) goes to zero and the numerator does not, so you are not going to have a limit forget i mentioned the algebra, although that is usually a good first step
cassieforlife5
  • cassieforlife5
okay I thought the question was really weird so I put nonexistent as the limit before and just wanted to see if I had done something wrong. Thanks so much!!
anonymous
  • anonymous
yw
anonymous
  • anonymous
btw i guess it is worth mentioning that the domain of this beast is \((-1,\infty)\) so you cannot take the limit in any case a limit is two sided and you cannot approach \(-1\) from the left
anonymous
  • anonymous
ok that is wrong, because the domain excludes zero as well
anonymous
  • anonymous
but the above is still true
cassieforlife5
  • cassieforlife5
yeah I graphed it and it stopped at -1 and only continued onto the right which is why I assumed it was nonexistent

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