shelby1290
  • shelby1290
State the missing factor 4n^2+8n-60=(?)(n+5)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
what times \(n\) is \(4n^2\)?
shelby1290
  • shelby1290
4n?
anonymous
  • anonymous
yes

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anonymous
  • anonymous
and what times \(5\) gives \(-60\)?
shelby1290
  • shelby1290
-12
anonymous
  • anonymous
ok put them together are you are done
shelby1290
  • shelby1290
(4n-12)
anonymous
  • anonymous
yup
shelby1290
  • shelby1290
at the back of my textbook the answer is 4(n-3)
anonymous
  • anonymous
not really factored completely that would be \[4(n-3)(n+5)\]
anonymous
  • anonymous
yeah because the terms of \(4n-12\) have a common factor of 4
shelby1290
  • shelby1290
so you divide (4n-12) by 4 to get 4(n-3) ?
anonymous
  • anonymous
that is not "division" that is factoring, aka the distributive property \[4\times x-4\times 3=4(x-3)\]
shelby1290
  • shelby1290
ohh okay

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