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anonymous

  • one year ago

When you start with the function f^2(1)=2*2*1=4, if asked to repeat the process with an initial value of -1, does that mean :f^2(-1)=2*2*1 OR f^2(-1)=2*2*-1

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  1. anonymous
    • one year ago
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    I believe it is the second one.

  2. anonymous
    • one year ago
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    Thank you!

  3. anonymous
    • one year ago
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    i would love to know what \[ f^2(1)=2*2*1=4\] means

  4. anonymous
    • one year ago
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    It is reasonable to assume that because f(1) is there that the 1 in the equation is the x spot for f(x).

  5. anonymous
    • one year ago
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    f is either -2 or 2.

  6. anonymous
    • one year ago
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    That is what I thougt. Chaos Theory project.

  7. anonymous
    • one year ago
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    Probably 2. However, you can't really figure out how 2 is made because they don't give you the original function.

  8. anonymous
    • one year ago
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    f(x)=2x given initial value of 1

  9. anonymous
    • one year ago
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    iterations..f(1) = 2*1 = 2 , f^2(1) = 2*2*1 =4, f^3 (1) = 2*2*2*1=8. Replace initial value with -1 to find pattern.

  10. anonymous
    • one year ago
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    maybe it is \[f(x)=2x\\ f(-1)=-2\\ f^2(-1)=2\times 2\times -1=-4\\ f^3(-1)=-8 ...\\ f^n(-1)=-2^n\]

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