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anonymous
 one year ago
When you start with the function f^2(1)=2*2*1=4, if asked to repeat the process with an initial value of 1, does that mean :f^2(1)=2*2*1 OR f^2(1)=2*2*1
anonymous
 one year ago
When you start with the function f^2(1)=2*2*1=4, if asked to repeat the process with an initial value of 1, does that mean :f^2(1)=2*2*1 OR f^2(1)=2*2*1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I believe it is the second one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i would love to know what \[ f^2(1)=2*2*1=4\] means

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is reasonable to assume that because f(1) is there that the 1 in the equation is the x spot for f(x).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f is either 2 or 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is what I thougt. Chaos Theory project.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Probably 2. However, you can't really figure out how 2 is made because they don't give you the original function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(x)=2x given initial value of 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0iterations..f(1) = 2*1 = 2 , f^2(1) = 2*2*1 =4, f^3 (1) = 2*2*2*1=8. Replace initial value with 1 to find pattern.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe it is \[f(x)=2x\\ f(1)=2\\ f^2(1)=2\times 2\times 1=4\\ f^3(1)=8 ...\\ f^n(1)=2^n\]
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