A community for students.
Here's the question you clicked on:
 0 viewing
calculusxy
 one year ago
factoring quadratics..
calculusxy
 one year ago
factoring quadratics..

This Question is Closed

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Do you have a question? :3

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0Yeah i just posted it above but here it is anyway: \[5a^2  180\]

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4It didnt appear for a moment. Alright, let us begin!

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Let us first make the equation look clear to us. Let's factor out the 5.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4What can you say about x^236? Well, we know that there are 2 x's multiplied together. (x )(x ) We need to find the missing numbers. To find the missing numbers, we need to know the factors of 36 that when added together is zero and multiplied together is 36.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4\(a^236=a^2+0a+36\) Correct?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Those two equations are technically the same.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.40a means that there's two numbers that got added and were the same Those two numbers got multiplied and equaled to 36

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0wait.. i still don't understand that part about 0a

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Okay, here's a different way of explaining it a^2 means x*x 0a means number + number =0 36 means number * number =36 But, those numbers that got added and multiplied together have to be the same two numbers that got added and multiplied.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0but what two numbers would lead to that 0

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0but when multiplied will give me 36

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0ok so what's the next step?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Member, those numbers must equal 36 when multiplied, so it has to be a factor of 36.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Getting those two numbers is the last step

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.01, 2, 3, 4, 9, 12, 18, 36

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0okay so the answer would be : 5(a  6)(a + 6)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0would that be correct?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0thank you! i have another question.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[5n^2 + 5n  360\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Nice one @Zale101 There is a trick to avoid all of this for the future, it's called complete the square (of course if you understand it that is) \[\huge a^2b^2 = (ab)(a+b)\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.05(n^2 + n  75) factors of 75: 1,3,5,15,25,75 i can't find a number whose sum will be n or 1

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Nice one astro! Someone aleady sent me to try this, but i didn't want to change what i was gearing towards lol

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Dont look at the factors, sorry if i included this term. look at the 2 numbers that can be multiplied to get the last term but that's of course after factoring. Always look for the difference in squares. When we had 5(x^236) We can always use the rule astro given to us \((a^2−b^2)=(a−b)(a+b)\)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i didn't understand

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0@Zale101 Can you please hurry up a bit? I need to go to bed soon..

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Are you sure you factored it right?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i am not sure.. i desperately need help with this

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Try factoring it again.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4there was a mistake when you factored 5 out

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Now it should not be confusing :)

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Can you work that out?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0sorry i just need help with another question

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Show me your attempt on ths.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i don't know how to factor the 9 when i have the 12 or 4 (which can't be fully divisible by 9)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i don't know what to do

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4That's because all three terms dont have a common factor. This needs a slightly different approach.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4You have your two parenthesis prepared. Are you familiar with group factoring?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0can you plz help me quickly?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4So, before i group factor i'll try to use a different approach and this approach is examining what got added that made 12. Okay, 6v6v=12 v we can choose to replace 12v with 6v6v \(9v^2  12v + 4\) \(9v^2 6v6v + 4\)

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4@calculusxy how much do you know about group factoring?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4Learning how to group factor will save you when factoring these types of problems.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4This will help http://www.mesacc.edu/~scotz47781/mat120/notes/factoring/grouping/grouping.html

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0http://www.purplemath.com/modules/factquad2.htm i was looking at this . i don't know if this can be useful

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4You can try the bar model, it helps too!

Zale101
 one year ago
Best ResponseYou've already chosen the best response.4But after i arranged the equation with 6v6v replacing 12v, then group factoring would be easier from there.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.