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\[5a^2 - 180\]

Hi!

Hello!

Do you have a question? :3

Lol

nvm

Yeah i just posted it above but here it is anyway:
\[5a^2 - 180\]

It didnt appear for a moment. Alright, let us begin!

okay!

Let us first make the equation look clear to us. Let's factor out the 5.

5(a^2 - 36)

Awesome!

\(a^2-36=a^2+0a+36\)
Correct?

Those two equations are technically the same.

yes

wait.. i still don't understand that part about 0a

but what two numbers would lead to that 0

but when multiplied will give me 36

Correct!

ok so what's the next step?

Member, those numbers must equal 36 when multiplied, so it has to be a factor of 36.

Getting those two numbers is the last step

ok...

1, 2, 3, 4, 9, 12, 18, 36

factors of 36

|dw:1444099970567:dw|

6 oh!

okay so the answer would be :
5(a - 6)(a + 6)

would that be correct?

Yes :)

thank you! i have another question.

Does it make sense?

\[5n^2 + 5n - 360\]

and yes

5(n^2 + n - 75)
factors of 75: 1,3,5,15,25,75
i can't find a number whose sum will be n or 1

Haha, I see

i didn't understand

@Zale101 Can you please hurry up a bit? I need to go to bed soon..

Are you sure you factored it right?

i am not sure.. i desperately need help with this

Try factoring it again.

there was a mistake when you factored 5 out

5(n^2 + 1n - 72)

Much better

Now it should not be confusing :)

Can you work that out?

5(n+9)(n-8)

Perfect.

sorry i just need help with another question

9v^2 - 12v + 4

Show me your attempt on ths.

i don't know how to factor the 9 when i have the 12 or 4 (which can't be fully divisible by 9)

i don't know what to do

That's because all three terms dont have a common factor. This needs a slightly different approach.

You have your two parenthesis prepared. Are you familiar with group factoring?

not that much

can you plz help me quickly?

@calculusxy how much do you know about group factoring?

Learning how to group factor will save you when factoring these types of problems.

This will help http://www.mesacc.edu/~scotz47781/mat120/notes/factoring/grouping/grouping.html

You can try the bar model, it helps too!

okay thanks! :)