Will fan and medal!!
Give the oxidation number of Nitrogen in each of the following compounds or ions:
a) N2O
b)Ca(NO3)2
c)NH4 ^+
d)N2H4
e)Mg3N2
Please explain how you got them

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- Photon336

Let's take c) first
1. first we look to see if there's any kind of charge on the molecule
2. then we look for the oxidation states of the element(s)
3. we multiply oxidation state by the number of atoms for that element
4. add them all up.
so for
\[NH_{4}^{+}\]
We have 1 atom of nitrogen and 4 atoms of hydrogen.
Hydrogen has an oxidation state of +1 and there are four atoms right? so that's +4
we realize that the charge on our compound is +1 so the oxidation states must sum up to +1. Now we have +4 for hydrogen, and what oxidation state for nitrogen will give us +1 total. that's -3.
so nitrogen is -3 and hydrogen is +1
-3 + 4 = +1
try choice D and tell me what you get

- Photon336

\[N_{2}H_{4} \] try this one it's one of the choices @Shaekitchen

- anonymous

im thinking aboout it but im getting no where just give me a min @Photon336

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Im sorry im still not quite understanding @Photon336 Im nnot sure how I find what they add up to

- Photon336

@Shaekitchen first step is there a charge on N2H4 ?

- anonymous

How do i tell like i know that H has 1+ and theres 4 of them so 4+ right? @Photon336

- Photon336

yes correct

- Photon336

@shaekitchen read these rules below. these are the most important
YOU MUST LOOK TO SEE IF THERE IS A CHARGE ON THE MOLECULE, as in an ion.
IF THERE IS A CHARGE: The oxidation states must add up to that charge.
IF THERE IS NO CHARGE: the sum of the oxidation states = zero.

- anonymous

so in N2H4 theres no charge correct?? @Photon336

- Photon336

:) yep

- anonymous

sso then would the charge on N be 2+ ?

- Photon336

@Shaekitchen work out the entire problem and show me step by step.

- Photon336

this will help you understand this

- Photon336

- anonymous

I think i got it -6?

- anonymous

@Photon336 thats the only way i got it to cancel it out

- Photon336

|dw:1444101389055:dw|

- Photon336

|dw:1444101598809:dw|

- Photon336

@Shaekitchen please take a close look at how i set up the problem

- anonymous

okay I am going to try N2O
Thaat way you explained i really helped! @Photon336

- Photon336

@Shaekitchen Write out everything by using the drawing tool then post it here

- Photon336

But you need to make sure that you understand how I did it, does tat make sense?

- anonymous

My computer isnt letting me use the drawing tool
If i have N2O
I have a charge on O of -2 right? Theres so many charges on O how do I know which one to use? @Photon336

- Photon336

You always ask this question first before doing anything @Shaekitchen is there a charge on the molecule? oxygen almost always has a charge of -2

- anonymous

Theres no charge on this molecule but if O is 2- doesnt that mean that N would just be 1-?

- Photon336

almost, but no charge means oxidation states MUST = ZERO
ask your self if you summed up those numbers would you get zero?

- anonymous

I got it it would be +1 Im going to do the rest on my own as my computer is slow thank you for your help @Photon336

- Photon336

@Shaekitchen great job, it's +1 remember to use those rules. you should be able to figure out the rest now take care

Looking for something else?

Not the answer you are looking for? Search for more explanations.