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Compassionate
 one year ago
A baseball player has hit a ball. The height, y, of the ball x seconds after it is hit is given by y= 16x^2 + 80x + 3.
Compassionate
 one year ago
A baseball player has hit a ball. The height, y, of the ball x seconds after it is hit is given by y= 16x^2 + 80x + 3.

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Compassionate
 one year ago
Best ResponseYou've already chosen the best response.1So, I need to find the time it takes the ball to reach it's make height; it's max height, and the time it takes the ball to land on the ground. y= 16x^2 + 80x + 3 I can use the vertex formula to find the time of it's max height vertex = b/2a, 80/2(16) = 80/32 Vertex or time, then is equal to 2.5 seconds. Is the first part right?

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.1@Miracrown , @hartnn , @ganeshie8

Compassionate
 one year ago
Best ResponseYou've already chosen the best response.1y= 16x^2 + 80x + 3 Take 5/2 y = 16(5/2)^2 + 80(5/2) + 3 y = 16(25/4) + 80(5/2) + 3 y = 100 + 200 + 3 y = 103 So my points are (2.5, 103)... 2.5 being my time and 103 being my max height.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i guess there is a typo in first part. you forgot the negative sign `a=16` 80/32 would be negative 5/2 it's \[\frac{ 80 }{ 2(16) }=\frac{ 80 }{ 32 }=\frac{ 5 }{ 2 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.12nd part is correct y =103 ft (2.5 , 103) is the vertex point(max) \(\huge\color{green}{\checkmark}\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.13rd part `the time it takes the ball to land on the ground` (xintercept) pretty sure you can solve this one too. :=) goodluck!\o^_^o/
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