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Compassionate

  • one year ago

A baseball player has hit a ball. The height, y, of the ball x seconds after it is hit is given by y= -16x^2 + 80x + 3.

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  1. Compassionate
    • one year ago
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    So, I need to find the time it takes the ball to reach it's make height; it's max height, and the time it takes the ball to land on the ground. y= -16x^2 + 80x + 3 I can use the vertex formula to find the time of it's max height vertex = -b/2a, -80/2(16) = -80/32 Vertex or time, then is equal to 2.5 seconds. Is the first part right?

  2. Compassionate
    • one year ago
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    @Miracrown , @hartnn , @ganeshie8

  3. Compassionate
    • one year ago
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    @wio

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    • one year ago
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    @dan815

  5. Compassionate
    • one year ago
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    y= -16x^2 + 80x + 3 Take 5/2 y = -16(5/2)^2 + 80(5/2) + 3 y = -16(25/4) + 80(5/2) + 3 y = -100 + 200 + 3 y = 103 So my points are (2.5, 103)... 2.5 being my time and 103 being my max height.

  6. Nnesha
    • one year ago
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    i guess there is a typo in first part. you forgot the negative sign `a=-16` -80/32 would be negative 5/2 it's \[\frac{ -80 }{ 2(-16) }=\frac{ -80 }{ -32 }=\frac{ 5 }{ 2 }\]

  7. Nnesha
    • one year ago
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    2nd part is correct y =103 ft (2.5 , 103) is the vertex point(max) \(\huge\color{green}{\checkmark}\)

  8. Nnesha
    • one year ago
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    3rd part `the time it takes the ball to land on the ground` (x-intercept) pretty sure you can solve this one too. :=) goodluck!\o^_^o/

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