anonymous
  • anonymous
Jack and Jill exercise in a 25.0-m-long swimming pool. Jack swims nine lengths of the pool in 2 minutes and 22.3 seconds, while Jill, the faster swimmer, covers ten lengths in the same time interval. Find the average velocity and average speed of each swimmer.
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Hmmm, Lall appears to be slightly confused by the change in direction, which occurs each time the swimmers turn at the ends of the pool and requires an ACCELERATION. As Jill has completed an even number of lengths and hence returned to the starting point her average velocity must be zero. However, Jack has completed an odd number of lengths so must have a non-zero average velocity. i.e his DISPLACEMENT from the starting point divided by TIME taken is greater than zero. I hope this helps.
anonymous
  • anonymous
so i was wrong so i must delete the post above...
anonymous
  • anonymous
So would you go with 25.0 m of the pool and multiply it by 9 since he did it that many times to get the displacement then divide it by the 2 minutes and 22.3 seconds (about 142 seconds)?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
https://akk.li/pics/anne/jpg that should help
Michele_Laino
  • Michele_Laino
velocity is a vector quantity, whereas speed is an algebraic quantity. For example, If I swim two time the length of the pool then the average velocity is the zero vector |dw:1444183986824:dw|
Michele_Laino
  • Michele_Laino
whereas the average speed is: \[\frac{{2L}}{{\Delta t}}\] where \L\) is the length of the pool and \( \Delta t\) is time needed to swim the pool two times
Michele_Laino
  • Michele_Laino
oops... where \(L\) is...
anonymous
  • anonymous
So I would take 25.0/2 mins and 22.3 secs for the the speed?
Michele_Laino
  • Michele_Laino
In the case of Jake, his velocity is a vector whose magnitude is: \(25/142.3=...m/sec\) whereas the average speed is: \( (25 \cdot 9)/142.3=...m/sec\)
Michele_Laino
  • Michele_Laino
I meant average velocity, of course
anonymous
  • anonymous
So 1.58 m/s for the speed .18 m/s for the velocity

Looking for something else?

Not the answer you are looking for? Search for more explanations.