anonymous
  • anonymous
A cash register contains only five dollar and ten dollar bills. It contains twice as many five's as ten's and the total amount of money in the cash register is 580 dollars. How many ten's are in the cash register?
Mathematics
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SOLVED
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chestercat
  • chestercat
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DN_20
  • DN_20
So x = 5, y = 10, z= # of 5's have, and a= # of 10's have 2xz +ya =580 2 (5) z + 10a = 580 10z +10a = 580 10(z+a) = 580 z+a =58 We have twice as many fives than tens, so z = 2a Substitution Property of Equality 2a +a = 58 3a = 58 a = 19.333 So z= 38.667 So we have 19 bill of 10's and 38 bill of 5's, but the last one? 1/3 for 10's and 2/3 for 5's, so 19 1/3 bill of 10's and 38 2/3 bill of 5's
DN_20
  • DN_20
Sorry, I not totally sure if I did it right. But I hope that I'm right since I checked many time before I sent this.
anonymous
  • anonymous
what if the money was 680 would it be the same formula

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DN_20
  • DN_20
Yeah
DN_20
  • DN_20
The answers is crazy, since the bills cannot be in fraction
anonymous
  • anonymous
So if its 680, how many 10s would there be?
DN_20
  • DN_20
The number of 10s will be 22.667, while the 5s are 45.333

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