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anonymous

  • one year ago

Help with interval notation: My prof. Never explained interval notation, so I don't know how to write the answers to these... a) Determine the domain of the function f(x)= {1}{\sqrt{3 x+12}} Domain (in interval notation): Note: Write the answer in interval notation. If the answer includes more than one interval write the intervals separated by the union symbol, U. If needed enter -\infty as - infinity and \infty as infinity . b) Determine the domain of the function f(x) = {-4}/{x^{2}+8x} . I know a) is all real numbers except -4, and b) should be non-zero real numbers.

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  1. Astrophysics
    • one year ago
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    It has been a while since I've used this notation X_X, ok so your first function is \[f(x) = \frac{ 1 }{ \sqrt{3x+12} }\] so we have to solve what's under the square root for the domain \[3x+12>0 \implies x >- 4\] it's greater than 0 because it's under the square root and we cannot have negative in square roots. So our interval will be \[D:(-4, \infty)\] we used open brackets for -4 because we do not include it in our domain, - infinity, and infinity always have open brackets. If they were closed, it means included.

  2. anonymous
    • one year ago
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    Thank you!

  3. anonymous
    • one year ago
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    Can you explain the second one too? I know it has multiple intervals but I'm lost other than that.

  4. Astrophysics
    • one year ago
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    \[f(x) = - \frac{ 4 }{ x^2+8x }\] is this the function?

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