anonymous
  • anonymous
Urn A has 16 white and 10 red balls. Urn B has 2 white and 9 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a red ball is selected. What is the probability that the coin landed heads?
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@is3535
is3535
  • is3535
9 didve by 2=
anonymous
  • anonymous
how'd you get 9/2? @is3535

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More answers

is3535
  • is3535
Urn B has 2 white and 9 red balls
anonymous
  • anonymous
9/2 is 4.5 @is3535
is3535
  • is3535
that your answer
anonymous
  • anonymous
4.5?
anonymous
  • anonymous
4.5? its asking the probability? @is3535
anonymous
  • anonymous
@Leong @YoloShroom
is3535
  • is3535
oh im sry it will be 9
is3535
  • is3535
whic is biger 9 or 2
anonymous
  • anonymous
9
is3535
  • is3535
yea
is3535
  • is3535
9 is your answer
anonymous
  • anonymous
how? @is3535
is3535
  • is3535
Urn B has 2 white and 9 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a red ball is selected. What is the probability that the coin landed head,
anonymous
  • anonymous
are we doing some ratio??? or like....
is3535
  • is3535
|dw:1444156898622:dw|
anonymous
  • anonymous
its just saying, Suppose that a red ball is selected. What is the probability that the coin landed heads? @Leong
anonymous
  • anonymous
4.5 :v you take 9 divide for 2, like you got less ball mean less chance.
anonymous
  • anonymous
@dan815
anonymous
  • anonymous
@Shalante
Pulsified333
  • Pulsified333
Probability can not be more than 1
anonymous
  • anonymous
okay :v then if not one we should do some ratio here: 10 over 16, means that 0.625 chance that the A get to choose :v
anonymous
  • anonymous
i don't think thats right @Leong
anonymous
  • anonymous
@BAdhi
BAdhi
  • BAdhi
This involves conditional probability and total probability theorem @vzforever are you familiar with them?
anonymous
  • anonymous
yes @BAdhi
BAdhi
  • BAdhi
can you show me the given information written as the notation used in probability such as p(A) , p(B) etc
anonymous
  • anonymous
i don't understand @BAdhi
BAdhi
  • BAdhi
can you write down the given information in the mathematical notation? for example probability of choosing A => P(A)
anonymous
  • anonymous
Pr(A)= 1/2 Pr(B)= 1/2 @BAdhi
anonymous
  • anonymous
what next? @BAdhi
BAdhi
  • BAdhi
what about the probability of getting a red ball given that we have choosen A? can you show it in the notation?
anonymous
  • anonymous
Pr(AR)=10/26
BAdhi
  • BAdhi
umm, by P(AR) you mean \(P(A \cap R)\) ?
anonymous
  • anonymous
no its 10/42 @BAdhi
BAdhi
  • BAdhi
10/42 is the probability of choosing a red ball out of all the balls.. but you see, since its already given that A has been choosen the amount of balls are reduced to 26. And i still need the answer to the previous question @vzforever
anonymous
  • anonymous
whats ur previous question? @BAdhi
BAdhi
  • BAdhi
what do you mean by P(AR).. from what ive learned no such notation is used in prbability either it has to be \(P(A\cap R) , P(A\cup R), P(A|R)\) ??
anonymous
  • anonymous
yes ur right
anonymous
  • anonymous
what u said before was correct
BAdhi
  • BAdhi
ok.. what about the notation.. arent you going to answer my question?
anonymous
  • anonymous
i said yes its (P(A \cap R)\)
BAdhi
  • BAdhi
\(P(A\cap R)\) means the probility of choosing a red ball and choosing A in here event -> choosing A and choosing red ball has still not occured but what i asked was, probability of choosing a Red ball given that A is choosen. in here A has already being chosen
BAdhi
  • BAdhi
so the correct notation is \(P(R | A)\)
anonymous
  • anonymous
ok
BAdhi
  • BAdhi
similarly you can find P(B), P(R|B), P(W|B), P(W|A) so since the event -> turning head and the event -> choosing A are both same, what they are asking is, P(A|R)
anonymous
  • anonymous
ok so is it (1/2)/(10/42)
anonymous
  • anonymous
which is 5/42
BAdhi
  • BAdhi
so what you are saying is, \(P(A|R) = P(R)\times P(A)\) ??
anonymous
  • anonymous
can you explain to me? i need to get this done.
anonymous
  • anonymous
@kropot72
BAdhi
  • BAdhi
Its normal to get confused with the difference between \(P(A\cap R)\) and \(P(R|A)\) so I recommend you to read and look more into the explanation ive given in the previous post The definition of the conditional probability is, \(P(R|A) = \frac{P(R\cap A)}{P(A)}\) since P(R|A) and P(A) are known, you can find \(P(R\cap A)\) since what they are asking is P(A|R) , \(P(A|R) =\frac{P(A\cap R)}{P(R)} \) can \(P(A\cap R)\) is obtained in the previous step and hope you know how to find P(R)
anonymous
  • anonymous
ok so what do i do to solve this problem
anonymous
  • anonymous
we haven't even gotten there yet
anonymous
  • anonymous
@TQKMB
anonymous
  • anonymous
@BAdhi can we do the problem?
BAdhi
  • BAdhi
thats what im trying to do the whole time.. i dont wanna give you the answer straight forward, since itll be pretty useless. as a guidance let me state this, you have to find the values of the following variables from the given information straight forward P(A), P(R|A), P(R) with use of conditional probability definition (which ive given above) you have to find \(P(A\cap R)\) after that find P(A|R) with use of the same conditional probability definition (which is also given previously) what they are asking is the value of P(A|R)
anonymous
  • anonymous
ok
anonymous
  • anonymous
can u explain with numbers
BAdhi
  • BAdhi
it is really important to know the difference between P(A|R) and \(P(A \cap R) \) since , as you can see even in this problem they are applied so close together in problems Are you clear with the difference between them?
BAdhi
  • BAdhi
first give me what youve tried pls after that ill give the answer
anonymous
  • anonymous
110/299 and 299/462 are the answers I've gotten and neither are right. obviously i need help cause idk what I'm doing. and I've made a tree
anonymous
  • anonymous
@BAdhi
anonymous
  • anonymous
@dan815
BAdhi
  • BAdhi
can you show the steps too.. that would be a good starter

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