A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Urn A has 16 white and 10 red balls. Urn B has 2 white and 9 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a red ball is selected.
What is the probability that the coin landed heads?
anonymous
 one year ago
Urn A has 16 white and 10 red balls. Urn B has 2 white and 9 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a red ball is selected. What is the probability that the coin landed heads?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how'd you get 9/2? @is3535

is3535
 one year ago
Best ResponseYou've already chosen the best response.0Urn B has 2 white and 9 red balls

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04.5? its asking the probability? @is3535

is3535
 one year ago
Best ResponseYou've already chosen the best response.0Urn B has 2 white and 9 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a red ball is selected. What is the probability that the coin landed head,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are we doing some ratio??? or like....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its just saying, Suppose that a red ball is selected. What is the probability that the coin landed heads? @Leong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04.5 :v you take 9 divide for 2, like you got less ball mean less chance.

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.0Probability can not be more than 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay :v then if not one we should do some ratio here: 10 over 16, means that 0.625 chance that the A get to choose :v

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't think thats right @Leong

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1This involves conditional probability and total probability theorem @vzforever are you familiar with them?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1can you show me the given information written as the notation used in probability such as p(A) , p(B) etc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't understand @BAdhi

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1can you write down the given information in the mathematical notation? for example probability of choosing A => P(A)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Pr(A)= 1/2 Pr(B)= 1/2 @BAdhi

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1what about the probability of getting a red ball given that we have choosen A? can you show it in the notation?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1umm, by P(AR) you mean \(P(A \cap R)\) ?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.110/42 is the probability of choosing a red ball out of all the balls.. but you see, since its already given that A has been choosen the amount of balls are reduced to 26. And i still need the answer to the previous question @vzforever

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whats ur previous question? @BAdhi

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1what do you mean by P(AR).. from what ive learned no such notation is used in prbability either it has to be \(P(A\cap R) , P(A\cup R), P(AR)\) ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what u said before was correct

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1ok.. what about the notation.. arent you going to answer my question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i said yes its (P(A \cap R)\)

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1\(P(A\cap R)\) means the probility of choosing a red ball and choosing A in here event > choosing A and choosing red ball has still not occured but what i asked was, probability of choosing a Red ball given that A is choosen. in here A has already being chosen

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1so the correct notation is \(P(R  A)\)

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1similarly you can find P(B), P(RB), P(WB), P(WA) so since the event > turning head and the event > choosing A are both same, what they are asking is, P(AR)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so is it (1/2)/(10/42)

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1so what you are saying is, \(P(AR) = P(R)\times P(A)\) ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you explain to me? i need to get this done.

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1Its normal to get confused with the difference between \(P(A\cap R)\) and \(P(RA)\) so I recommend you to read and look more into the explanation ive given in the previous post The definition of the conditional probability is, \(P(RA) = \frac{P(R\cap A)}{P(A)}\) since P(RA) and P(A) are known, you can find \(P(R\cap A)\) since what they are asking is P(AR) , \(P(AR) =\frac{P(A\cap R)}{P(R)} \) can \(P(A\cap R)\) is obtained in the previous step and hope you know how to find P(R)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so what do i do to solve this problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we haven't even gotten there yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@BAdhi can we do the problem?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1thats what im trying to do the whole time.. i dont wanna give you the answer straight forward, since itll be pretty useless. as a guidance let me state this, you have to find the values of the following variables from the given information straight forward P(A), P(RA), P(R) with use of conditional probability definition (which ive given above) you have to find \(P(A\cap R)\) after that find P(AR) with use of the same conditional probability definition (which is also given previously) what they are asking is the value of P(AR)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u explain with numbers

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1it is really important to know the difference between P(AR) and \(P(A \cap R) \) since , as you can see even in this problem they are applied so close together in problems Are you clear with the difference between them?

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1first give me what youve tried pls after that ill give the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0110/299 and 299/462 are the answers I've gotten and neither are right. obviously i need help cause idk what I'm doing. and I've made a tree

BAdhi
 one year ago
Best ResponseYou've already chosen the best response.1can you show the steps too.. that would be a good starter
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.