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Pulsified333
 one year ago
Assume that the box contains 10 balls: 1 red, 5 green, and 4 blue. Two balls are drawn at random, one after the other without replacement.
What is the probability that the first ball was blue, given that the second was red
Pulsified333
 one year ago
Assume that the box contains 10 balls: 1 red, 5 green, and 4 blue. Two balls are drawn at random, one after the other without replacement. What is the probability that the first ball was blue, given that the second was red

This Question is Closed

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.1I tried this problem but my answer keeps coming out to be greater than 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm a little tricky cx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0theres 1 red 5 green and 4 blue and its asking whats the probability that the first ball was blue

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have choices? :)

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.1wait is this the way the formula for the answer should look (4/10*1/9)/((5/10*1/9)+(4/10*1/9)+(4/10*1/9))

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay solve it :) and see if its one of the choices for your question :) if you have any

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.1no its a blank we fill

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay i see :) do you do k12?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh nvm its a homeschooling thing cx

Pulsified333
 one year ago
Best ResponseYou've already chosen the best response.1I got the right answer :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyways ima try it out :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You did? Well congrats :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you need help with anything else just ask cx even tho i did really get to help xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Tag me into questions cx
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