Assume that the box contains 10 balls: 1 red, 5 green, and 4 blue. Two balls are drawn at random, one after the other without replacement.
What is the probability that the first ball was blue, given that the second was red

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- Pulsified333

- katieb

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- Pulsified333

I tried this problem but my answer keeps coming out to be greater than 1

- anonymous

hmmm a little tricky cx

- anonymous

Okay so think

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- anonymous

theres 1 red 5 green and 4 blue and its asking whats the probability that the first ball was blue

- anonymous

Do you have choices? :)

- Pulsified333

wait is this the way the formula for the answer should look (4/10*1/9)/((5/10*1/9)+(4/10*1/9)+(4/10*1/9))

- anonymous

Okay solve it :) and see if its one of the choices for your question :-) if you have any

- Pulsified333

no its a blank we fill

- anonymous

Okay i see :) do you do k12?

- Pulsified333

k12?

- anonymous

Oh nvm its a homeschooling thing cx

- Pulsified333

I got the right answer :D

- anonymous

Anyways ima try it out :-)

- anonymous

You did? Well congrats :)

- Pulsified333

yeah

- anonymous

If you need help with anything else just ask cx even tho i did really get to help xD

- anonymous

Tag me into questions cx

- Pulsified333

okay thanks :)

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