Pulsified333
  • Pulsified333
Assume that the box contains 10 balls: 1 red, 5 green, and 4 blue. Two balls are drawn at random, one after the other without replacement. What is the probability that the first ball was blue, given that the second was red
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Pulsified333
  • Pulsified333
I tried this problem but my answer keeps coming out to be greater than 1
anonymous
  • anonymous
hmmm a little tricky cx
anonymous
  • anonymous
Okay so think

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More answers

anonymous
  • anonymous
theres 1 red 5 green and 4 blue and its asking whats the probability that the first ball was blue
anonymous
  • anonymous
Do you have choices? :)
Pulsified333
  • Pulsified333
wait is this the way the formula for the answer should look (4/10*1/9)/((5/10*1/9)+(4/10*1/9)+(4/10*1/9))
anonymous
  • anonymous
Okay solve it :) and see if its one of the choices for your question :-) if you have any
Pulsified333
  • Pulsified333
no its a blank we fill
anonymous
  • anonymous
Okay i see :) do you do k12?
Pulsified333
  • Pulsified333
k12?
anonymous
  • anonymous
Oh nvm its a homeschooling thing cx
Pulsified333
  • Pulsified333
I got the right answer :D
anonymous
  • anonymous
Anyways ima try it out :-)
anonymous
  • anonymous
You did? Well congrats :)
Pulsified333
  • Pulsified333
yeah
anonymous
  • anonymous
If you need help with anything else just ask cx even tho i did really get to help xD
anonymous
  • anonymous
Tag me into questions cx
Pulsified333
  • Pulsified333
okay thanks :)

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