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Pulsified333

  • one year ago

Assume that the box contains 10 balls: 1 red, 5 green, and 4 blue. Two balls are drawn at random, one after the other without replacement. What is the probability that the first ball was blue, given that the second was red

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  1. Pulsified333
    • one year ago
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    I tried this problem but my answer keeps coming out to be greater than 1

  2. anonymous
    • one year ago
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    hmmm a little tricky cx

  3. anonymous
    • one year ago
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    Okay so think

  4. anonymous
    • one year ago
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    theres 1 red 5 green and 4 blue and its asking whats the probability that the first ball was blue

  5. anonymous
    • one year ago
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    Do you have choices? :)

  6. Pulsified333
    • one year ago
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    wait is this the way the formula for the answer should look (4/10*1/9)/((5/10*1/9)+(4/10*1/9)+(4/10*1/9))

  7. anonymous
    • one year ago
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    Okay solve it :) and see if its one of the choices for your question :-) if you have any

  8. Pulsified333
    • one year ago
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    no its a blank we fill

  9. anonymous
    • one year ago
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    Okay i see :) do you do k12?

  10. Pulsified333
    • one year ago
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    k12?

  11. anonymous
    • one year ago
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    Oh nvm its a homeschooling thing cx

  12. Pulsified333
    • one year ago
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    I got the right answer :D

  13. anonymous
    • one year ago
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    Anyways ima try it out :-)

  14. anonymous
    • one year ago
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    You did? Well congrats :)

  15. Pulsified333
    • one year ago
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    yeah

  16. anonymous
    • one year ago
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    If you need help with anything else just ask cx even tho i did really get to help xD

  17. anonymous
    • one year ago
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    Tag me into questions cx

  18. Pulsified333
    • one year ago
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    okay thanks :)

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spraguer (Moderator)
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