MTALHAHASSAN2
  • MTALHAHASSAN2
can someone plz help withworksheet
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
MTALHAHASSAN2
  • MTALHAHASSAN2
anonymous
  • anonymous
u r of 10th class?
anonymous
  • anonymous
cbse?

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MTALHAHASSAN2
  • MTALHAHASSAN2
yes
MTALHAHASSAN2
  • MTALHAHASSAN2
are you able to help
MTALHAHASSAN2
  • MTALHAHASSAN2
@lall are you there
MTALHAHASSAN2
  • MTALHAHASSAN2
@inkyvoyd
MTALHAHASSAN2
  • MTALHAHASSAN2
i found out the average and the range
anonymous
  • anonymous
so u have a problem with uncertainty?
MTALHAHASSAN2
  • MTALHAHASSAN2
yeah
anonymous
  • anonymous
firstly subtract all the speed with avrage speed and take their modulus( consider their magnitude only)
anonymous
  • anonymous
eg.
anonymous
  • anonymous
what is first average?
anonymous
  • anonymous
332.1 m/s = av. speed
MTALHAHASSAN2
  • MTALHAHASSAN2
332.1
anonymous
  • anonymous
\[v _{av } -v _{1} =\Delta v _{1}\]
anonymous
  • anonymous
332.1-331.9 =
anonymous
  • anonymous
0.2 m/s
MTALHAHASSAN2
  • MTALHAHASSAN2
what is it??
anonymous
  • anonymous
actually it is the difference of the speed from average speed....
anonymous
  • anonymous
now u take the differences in each case and take their average...
MTALHAHASSAN2
  • MTALHAHASSAN2
wait which one are we doing
MTALHAHASSAN2
  • MTALHAHASSAN2
are we finding the average or uncertainty
anonymous
  • anonymous
uncertainity
anonymous
  • anonymous
it is the method to find uncertainity
anonymous
  • anonymous
topic of 11th class
MTALHAHASSAN2
  • MTALHAHASSAN2
so for the first be the difference of the speed from average speed.... is 0.2 right
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
ist one i hav shown so i started from 2.......
anonymous
  • anonymous
u hav to take modulus in each case i.e. | | do u know what is modulus?
MTALHAHASSAN2
  • MTALHAHASSAN2
i don't
anonymous
  • anonymous
like in the third u got a -ve sign....so modulus is used remove to remove that -ve sign...
MTALHAHASSAN2
  • MTALHAHASSAN2
wait are you doing the range or uncertainly
anonymous
  • anonymous
|-0.4| =0.4 m/s
anonymous
  • anonymous
uncertainity
MTALHAHASSAN2
  • MTALHAHASSAN2
what is the formula for finding the uncertainty
anonymous
  • anonymous
so u get all those values that are the differences from mean that ar 0.2, 0.1, 0.4 , 0.1 , 0.0..... so take average difference...
anonymous
  • anonymous
( 0.2+ 0.1+ 0.4 +0.1 + 0.0 ) /5 = 0.8/5
anonymous
  • anonymous
thus formula for uncertainity is \[v _{av}- \Delta v _{av}\]
anonymous
  • anonymous
do u got it?
MTALHAHASSAN2
  • MTALHAHASSAN2
sorry but i don't get that why are you putting 332.1
MTALHAHASSAN2
  • MTALHAHASSAN2
i mean in the sheet which you send me thoy
anonymous
  • anonymous
what is difference b/w the average speed to the observed speed int he first case....
anonymous
  • anonymous
332.1 is average speed
MTALHAHASSAN2
  • MTALHAHASSAN2
yes
MTALHAHASSAN2
  • MTALHAHASSAN2
range is 0.6
anonymous
  • anonymous
u dont need range at all to find the uncertainty
MTALHAHASSAN2
  • MTALHAHASSAN2
oh ok i am just making sure do i get the correct range
anonymous
  • anonymous
"the difference b/w the average speed to the observed speed " do u get this statement?
anonymous
  • anonymous
tell me?
MTALHAHASSAN2
  • MTALHAHASSAN2
yes i do
anonymous
  • anonymous
so then u take average of that all differences....
anonymous
  • anonymous
that is \[\Delta v _{av}\]
MTALHAHASSAN2
  • MTALHAHASSAN2
which i get for the first is 332.1
MTALHAHASSAN2
  • MTALHAHASSAN2
the average
anonymous
  • anonymous
average - 331.9
anonymous
  • anonymous
average -332=
anonymous
  • anonymous
average - 332.5 =
anonymous
  • anonymous
average -332 =
MTALHAHASSAN2
  • MTALHAHASSAN2
how you get that average
anonymous
  • anonymous
average- 332.1 =
anonymous
  • anonymous
these are the differences from the AVERAGE VELOCITY
anonymous
  • anonymous
so the next AVERAGE of those DIFFERENCES.....
MTALHAHASSAN2
  • MTALHAHASSAN2
for finding the average are we adding all the number and divide that by the number of trials
anonymous
  • anonymous
would give u \[\Delta v _{av}\]
anonymous
  • anonymous
yes for normal average...
anonymous
  • anonymous
are u not told how to solve this wok sht in school
MTALHAHASSAN2
  • MTALHAHASSAN2
i think they do but i forget
anonymous
  • anonymous
these concepts are of 11th class?
anonymous
  • anonymous
so ar u getting the missing links...
MTALHAHASSAN2
  • MTALHAHASSAN2
for finding the range are we just doing max-min
anonymous
  • anonymous
yes of course
anonymous
  • anonymous
in ur wk sht u just have to give \[\Delta v _{av}\]
MTALHAHASSAN2
  • MTALHAHASSAN2
can you plz do we a favour and review it the last time
MTALHAHASSAN2
  • MTALHAHASSAN2
i mean the uncertainly
anonymous
  • anonymous
let me solve it on the sheet and i will send the photo...u will be able to see the whole procedure
MTALHAHASSAN2
  • MTALHAHASSAN2
oh yeah thnx man
anonymous
  • anonymous
i hav taken too many pic as it was not clear
anonymous
  • anonymous
ar u getting
anonymous
  • anonymous
one significant fig is one digit after decimal place
MTALHAHASSAN2
  • MTALHAHASSAN2
oh ok thnx a lot

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