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VCabral1134
 one year ago
I need help will give medal and fan!!
5x^33 if x<7
f(x)= 2x^23 if 7<_ x<8 evaluate f(x) for x=7
6+2x if x>_8
VCabral1134
 one year ago
I need help will give medal and fan!! 5x^33 if x<7 f(x)= 2x^23 if 7<_ x<8 evaluate f(x) for x=7 6+2x if x>_8

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@AlexanderPhantomhive @Firez @hartnn

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0@KyanTheDoodle @Michele_Laino @texaschic101

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0I need help can someone explain this to me?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1there is a jump type discontinuity at x=7

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0ok what else? I don't understand, I have to find a number @Michele_Laino

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1oops.. I meant at x=7

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can compute the jump of the function at x = 7, as below: \[\begin{gathered} h\left( {  7} \right) = \mathop {\lim }\limits_{x \to  7 + } f\left( x \right)  \mathop {\lim }\limits_{x \to  7  } f\left( x \right) = \hfill \\ \hfill \\ = 2 \cdot {\left( {  7} \right)^2}  3  5 \cdot {\left( {  7} \right)^3} + 3 \hfill \\ \end{gathered} \]

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0do i solve the equation that you provided

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0is the answer 1,807 ?? @Michele_Laino

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0ok maybe I did something wrong

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can write this: \[\begin{gathered} h\left( x \right) = \left( {2{x^2}  3} \right)  \left( {5{x^3}  3} \right) = \hfill \\ \hfill \\ = 2{x^2}  3  5{x^3} + 3 = 2{x^2}  5{x^3} \hfill \\ \end{gathered} \] now, please try to substitute \(x=7\), what do you get?

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.02* (49)  3  5 * (343) + 3 98  3  (1715) +3 95  (1712) 1807

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have: 983+1715+3=...?

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.01813 @Michele_Laino

VCabral1134
 one year ago
Best ResponseYou've already chosen the best response.0Ok thank you so much!
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