VCabral1134
  • VCabral1134
I need help will give medal and fan!! 5x^3-3 if x<-7 f(x)= 2x^2-3 if -7<_ x<8 evaluate f(x) for x=-7 6+2x if x>_8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@AlexanderPhantomhive @Firez @hartnn
VCabral1134
  • VCabral1134
@KyanTheDoodle @Michele_Laino @texaschic101
VCabral1134
  • VCabral1134
I need help can someone explain this to me?

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Michele_Laino
  • Michele_Laino
there is a jump type discontinuity at x=7
VCabral1134
  • VCabral1134
ok what else? I don't understand, I have to find a number @Michele_Laino
Michele_Laino
  • Michele_Laino
oops.. I meant at x=-7
Michele_Laino
  • Michele_Laino
we can compute the jump of the function at x = -7, as below: \[\begin{gathered} h\left( { - 7} \right) = \mathop {\lim }\limits_{x \to - 7 + } f\left( x \right) - \mathop {\lim }\limits_{x \to - 7 - } f\left( x \right) = \hfill \\ \hfill \\ = 2 \cdot {\left( { - 7} \right)^2} - 3 - 5 \cdot {\left( { - 7} \right)^3} + 3 \hfill \\ \end{gathered} \]
VCabral1134
  • VCabral1134
ok
VCabral1134
  • VCabral1134
do i solve the equation that you provided
VCabral1134
  • VCabral1134
@TheSmartOne
VCabral1134
  • VCabral1134
is the answer 1,807 ?? @Michele_Laino
Michele_Laino
  • Michele_Laino
I got 1,813
VCabral1134
  • VCabral1134
ok maybe I did something wrong
Michele_Laino
  • Michele_Laino
we can write this: \[\begin{gathered} h\left( x \right) = \left( {2{x^2} - 3} \right) - \left( {5{x^3} - 3} \right) = \hfill \\ \hfill \\ = 2{x^2} - 3 - 5{x^3} + 3 = 2{x^2} - 5{x^3} \hfill \\ \end{gathered} \] now, please try to substitute \(x=-7\), what do you get?
VCabral1134
  • VCabral1134
2* (49) - 3 - 5 * (-343) + 3 98 - 3 - (-1715) +3 95 - (-1712) 1807
VCabral1134
  • VCabral1134
@Michele_Laino
Michele_Laino
  • Michele_Laino
we have: 98-3+1715+3=...?
VCabral1134
  • VCabral1134
1813
VCabral1134
  • VCabral1134
1813 @Michele_Laino
Michele_Laino
  • Michele_Laino
correct!
VCabral1134
  • VCabral1134
Ok thank you so much!

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