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VCabral1134

  • one year ago

I need help will give medal and fan!! 5x^3-3 if x<-7 f(x)= 2x^2-3 if -7<_ x<8 evaluate f(x) for x=-7 6+2x if x>_8

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  1. anonymous
    • one year ago
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    @AlexanderPhantomhive @Firez @hartnn

  2. VCabral1134
    • one year ago
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    @KyanTheDoodle @Michele_Laino @texaschic101

  3. VCabral1134
    • one year ago
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    I need help can someone explain this to me?

  4. Michele_Laino
    • one year ago
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    there is a jump type discontinuity at x=7

  5. VCabral1134
    • one year ago
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    ok what else? I don't understand, I have to find a number @Michele_Laino

  6. Michele_Laino
    • one year ago
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    oops.. I meant at x=-7

  7. Michele_Laino
    • one year ago
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    we can compute the jump of the function at x = -7, as below: \[\begin{gathered} h\left( { - 7} \right) = \mathop {\lim }\limits_{x \to - 7 + } f\left( x \right) - \mathop {\lim }\limits_{x \to - 7 - } f\left( x \right) = \hfill \\ \hfill \\ = 2 \cdot {\left( { - 7} \right)^2} - 3 - 5 \cdot {\left( { - 7} \right)^3} + 3 \hfill \\ \end{gathered} \]

  8. VCabral1134
    • one year ago
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    ok

  9. VCabral1134
    • one year ago
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    do i solve the equation that you provided

  10. VCabral1134
    • one year ago
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    @TheSmartOne

  11. VCabral1134
    • one year ago
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    is the answer 1,807 ?? @Michele_Laino

  12. Michele_Laino
    • one year ago
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    I got 1,813

  13. VCabral1134
    • one year ago
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    ok maybe I did something wrong

  14. Michele_Laino
    • one year ago
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    we can write this: \[\begin{gathered} h\left( x \right) = \left( {2{x^2} - 3} \right) - \left( {5{x^3} - 3} \right) = \hfill \\ \hfill \\ = 2{x^2} - 3 - 5{x^3} + 3 = 2{x^2} - 5{x^3} \hfill \\ \end{gathered} \] now, please try to substitute \(x=-7\), what do you get?

  15. VCabral1134
    • one year ago
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    2* (49) - 3 - 5 * (-343) + 3 98 - 3 - (-1715) +3 95 - (-1712) 1807

  16. VCabral1134
    • one year ago
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    @Michele_Laino

  17. Michele_Laino
    • one year ago
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    we have: 98-3+1715+3=...?

  18. VCabral1134
    • one year ago
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    1813

  19. VCabral1134
    • one year ago
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    1813 @Michele_Laino

  20. Michele_Laino
    • one year ago
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    correct!

  21. VCabral1134
    • one year ago
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    Ok thank you so much!

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