I need help will give medal and fan!! 5x^3-3 if x<-7 f(x)= 2x^2-3 if -7<_ x<8 evaluate f(x) for x=-7 6+2x if x>_8

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I need help will give medal and fan!! 5x^3-3 if x<-7 f(x)= 2x^2-3 if -7<_ x<8 evaluate f(x) for x=-7 6+2x if x>_8

Mathematics
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there is a jump type discontinuity at x=7
ok what else? I don't understand, I have to find a number @Michele_Laino
oops.. I meant at x=-7
we can compute the jump of the function at x = -7, as below: \[\begin{gathered} h\left( { - 7} \right) = \mathop {\lim }\limits_{x \to - 7 + } f\left( x \right) - \mathop {\lim }\limits_{x \to - 7 - } f\left( x \right) = \hfill \\ \hfill \\ = 2 \cdot {\left( { - 7} \right)^2} - 3 - 5 \cdot {\left( { - 7} \right)^3} + 3 \hfill \\ \end{gathered} \]
ok
do i solve the equation that you provided
is the answer 1,807 ?? @Michele_Laino
I got 1,813
ok maybe I did something wrong
we can write this: \[\begin{gathered} h\left( x \right) = \left( {2{x^2} - 3} \right) - \left( {5{x^3} - 3} \right) = \hfill \\ \hfill \\ = 2{x^2} - 3 - 5{x^3} + 3 = 2{x^2} - 5{x^3} \hfill \\ \end{gathered} \] now, please try to substitute \(x=-7\), what do you get?
2* (49) - 3 - 5 * (-343) + 3 98 - 3 - (-1715) +3 95 - (-1712) 1807
we have: 98-3+1715+3=...?
1813
correct!
Ok thank you so much!

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