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1)
\[f(x)=x \sqrt{2+x^2}\]
2)
\[f(x)=x|x|+1\]
3)
\[f(x)=\]||dw:1444147581351:dw|

So ummm

Confusing stuff? :d

hmm

haha yeah, it is!! so, when its onto and one to one its bijective, yeah?

yes c:

Hmm sorry mr koala :c
my brain being stupid today.
lemme see if smart guy can help
@ganeshie8

but isnt that one of the terms of being a bijective equation?

isn't `that`?
that what? :o

Are we looking at a certain question above?

oh sorry, isnt that one of the conditions i mean

If a function is onto and one-to-one then it is bijective.

now what are the codomains for which these function are defined?

basically we just want to show every element of the codomain gets hit

and how do we show that?

I was asking about your codomain
you need to answer that question first

it is B? or what?

I don't know... It should be given.

These questions area weird if they don't get you the domain and codomain

Like it should say let f:A->B be defined by f(x)=something goes here

B=Vf

where A and B are sets numbers given

yeah, but it says under the assignment B=Vf for every case

what does that mean

value amount

I hope this shows why we need to know the domain and codomain

you can show in a similar way the negative reals also get hit

Okey, so this is the tactics for all of these ?

this is hard stuff..

another example:
|dw:1444153993613:dw|

|dw:1444154104419:dw|

where y is a number of the codomain

|dw:1444154427501:dw|