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anonymous
 one year ago
50 grams of propane (c3h8) is oxidized (combusted/burned) completely to co2 and h20 by reaction with 300 grams of pure oxygen (o2). What is the composition of the reaction products in grams?
grams of c02=
grams of h20=
grams of c3h8=
grams of 02=
anonymous
 one year ago
50 grams of propane (c3h8) is oxidized (combusted/burned) completely to co2 and h20 by reaction with 300 grams of pure oxygen (o2). What is the composition of the reaction products in grams? grams of c02= grams of h20= grams of c3h8= grams of 02=

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3first write the balanced equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did but i am still confused like i balanced it like this: C3H8+5o2>3Co2+4h20

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3find the no. of moles of C3H8 moles = mass divided by molar mass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what should i do after i get the moles

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3moles of CO2 = 3 times of moles of C3H8

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3use the same equation moles = mass/ molar mass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0should i find the moles of all of them first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now how do i find the mass

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3mass = molar mass * moles

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the masses i got don't add up to 350 idk y

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3Mass of CO2 is 150 g approximately

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3Mass of H2O = 81.8 g approximately

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3Looking at the stoichiometric ratio we can see the ratio of moles of C3H8: O2 is 1:5 That means 1 moles of C3H8 reacts with 5 moles of O2 We know the no. of moles of C3H8 that was 1.136 right? That means to oxidise C3H8 completely we need (1.136 *5) moles right? so no. of moles of O2 needed = 5.68 moles But we are said that we have 300 g of O2 Using that mass we should find the no. of moles of O2 . The total O2 present Total moles = 300/32 = 9.375 But to complete the reaction we only need 5.68 moles of O2 That means O2 is in excess. So that will remain in the products side. The remaining would be 9.375  5.68 = 3.695 moles Now we can find the mass of O2 remaining mass = 3.695 * 32= 118.24g

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay thank you so much

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.3No problem ... hope you got it :)
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