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anonymous

  • one year ago

50 grams of propane (c3h8) is oxidized (combusted/burned) completely to co2 and h20 by reaction with 300 grams of pure oxygen (o2). What is the composition of the reaction products in grams? grams of c02= grams of h20= grams of c3h8= grams of 02=

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  1. Rushwr
    • one year ago
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    first write the balanced equation

  2. anonymous
    • one year ago
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    i did but i am still confused like i balanced it like this: C3H8+5o2-->3Co2+4h20

  3. Rushwr
    • one year ago
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    yep

  4. Rushwr
    • one year ago
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    find the no. of moles of C3H8 moles = mass divided by molar mass

  5. anonymous
    • one year ago
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    what should i do after i get the moles

  6. Rushwr
    • one year ago
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    moles of CO2 = 3 times of moles of C3H8

  7. Rushwr
    • one year ago
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    use the same equation moles = mass/ molar mass

  8. Rushwr
    • one year ago
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    then we can find mass

  9. Rushwr
    • one year ago
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    of CO2

  10. anonymous
    • one year ago
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    should i find the moles of all of them first

  11. Rushwr
    • one year ago
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    yeah yeah

  12. anonymous
    • one year ago
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    oh ok

  13. anonymous
    • one year ago
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    now how do i find the mass

  14. Rushwr
    • one year ago
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    mass = molar mass * moles

  15. anonymous
    • one year ago
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    the masses i got don't add up to 350 idk y

  16. anonymous
    • one year ago
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    thank you though :)

  17. Rushwr
    • one year ago
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    wait I'll check for u

  18. Rushwr
    • one year ago
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    Mass of CO2 is 150 g approximately

  19. Rushwr
    • one year ago
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    Mass of H2O = 81.8 g approximately

  20. Rushwr
    • one year ago
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    Looking at the stoichiometric ratio we can see the ratio of moles of C3H8: O2 is 1:5 That means 1 moles of C3H8 reacts with 5 moles of O2 We know the no. of moles of C3H8 that was 1.136 right? That means to oxidise C3H8 completely we need (1.136 *5) moles right? so no. of moles of O2 needed = 5.68 moles But we are said that we have 300 g of O2 Using that mass we should find the no. of moles of O2 . The total O2 present Total moles = 300/32 = 9.375 But to complete the reaction we only need 5.68 moles of O2 That means O2 is in excess. So that will remain in the products side. The remaining would be 9.375 - 5.68 = 3.695 moles Now we can find the mass of O2 remaining mass = 3.695 * 32= 118.24g

  21. anonymous
    • one year ago
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    oh okay thank you so much

  22. Rushwr
    • one year ago
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    No problem ... hope you got it :)

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