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anonymous
 one year ago
A 14 kg rock starting from rest free falls through a distance of 5.0 m with no air resistance. Find the momentum change of the rock caused by its fall and the resulting change in the magnitude of earth’s velocity. Earth’s mass is 6.0 × 10^24 kg. Show all your work, assuming the rockearth system is closed.
anonymous
 one year ago
A 14 kg rock starting from rest free falls through a distance of 5.0 m with no air resistance. Find the momentum change of the rock caused by its fall and the resulting change in the magnitude of earth’s velocity. Earth’s mass is 6.0 × 10^24 kg. Show all your work, assuming the rockearth system is closed.

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Chealyn98
 one year ago
Best ResponseYou've already chosen the best response.0for the rock: P0 = mv0 = (14)(0) = 0 Pf = 14vf, so we need to find vf vf = v0 + at = 0 + (9.8)t, we need to find t xf = x0 + v0t + (1/2)at^2 5 = 0 + 0t + (1/2)(9.8)t^2 1.0102 = t so vf = (9.8)(1.1012) = 9.89996 Pf = 14(9.89996) = 138.6 kg m/s Change in momentum is 138.6 kg m/s In a closed system, momentum is conserved, so a change in momentum for one body must be accompanied by a corresponding change in another body. So the earth's momentum must change in the same magnitude but opposite direction to the rock's change in momentum. P = mv 138.6 = (6.0 x10^24)v 138.6/(6.0 x 10^24) = v 2.31 X10^ 23 m/s = v So, as the rock falls toward the Earth, the Earth moves up toward the rock.
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