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## KJ4UTS one year ago If a ball is dropped near the surface of the earth, then the distance it falls is directly proportional to the square of the time it has fallen. A ball is dropped over the edge of a vertical cliff and falls 39.2 meters in two seconds. Determine the distance (in meters) the ball would have dropped in 3.5 seconds. The ball would have dropped ____ meters. Round your answer to two decimal places.

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1. KJ4UTS

2. MrNood

it tells you the distance is proportional to the square of the time so distance = kt^2 $\frac{ d1 }{ d2 } =\frac{ t1^{2} }{ t2^{2} }$ you know all except d2 - so solve for d2

3. KJ4UTS

So I plug in 32.9 and 2 (seconds) in?

4. MrNood

in the first scenario d=32.9 and t=2 in the second scenario d is unknown and t= 3.5 put those 3 values into the equation to solve the unknown distance

5. KJ4UTS

32.9/2^2=k ?

6. KJ4UTS

Is that how I set the formula up because it would be 9.8 then?

7. KJ4UTS

@MrNood

8. KJ4UTS

32.9/3.5^2=3.2

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