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have you learned
rate * time = distance
or
speed * time = distance
or
velocity * time = distance
?

yes I have

For
traveled downstream
first, what is the speed of the boat going with the current?

I don't remember how to do this. I'm I suppose to multiply?

Umm I really don't mean to sound stupid, but 1 maybe. not very fast

you will be going at a speed of "y"
(they tell us let y represent the speed of the water.)

though y is a letter, it means "speed of the current" (it's short-hand)

hmm y+ x+y?

(x+y)*1=d

(x+y)*3.6h=d

Write an expression for the distance traveled downstream using 3 h for the time.

(x+y)*3h=d

now you need to the speed going upstream
any ideas ?

(x+y)*3.6=d
or
3.6(x+y)=d

(x+y) is how fast you go downstream
when you go upstream, you go slower

would it be x-y

ok would we still multiply the time like (x-y)*3.6=d

yes, exactly.
now you have part a)
3(x+y)= d
3.6(x-y) = d

It does make since d is the outcome in both equations

expressions i mean

ok 3x+3y=3.6x-3.6y do we then add like terms?

yes,

3x+3y=3.6x-3.6y
I would add 3.6y to both sides
3x + 3y + 3.6y = 3.6x -3.6y +3.6y

you get
3x+6.6y = 3.6x
now add -3x to both sides

6.6y=-0.833

you lost the x?
what is 3.6x - 3x ?

0.6x

yes, so you get
3x+6.6y = 3.6x
6.6y = 0.6 x
now divide both sides by 6.6
what do we get ?

11

you get
\[ y= \frac{0.6}{6.6} x\]
that simplifies to
\[ y = \frac{1}{11} x \]

Ok I get it

ok, so if i multiply it turns back into 1x and 11x so I'm really sure how to solve this

Thats what I meant to say 1/11 because I did cross multiply

ok, 0.11

9.09 after multiplying 100

and add a % sign (which is how we show we multiplied by 100)
9.09%

9.09% got it

Thank you so very much. I really appreciate your help.