A community for students.
Here's the question you clicked on:
 0 viewing
calculusxy
 one year ago
factoring quadratic expressions
calculusxy
 one year ago
factoring quadratic expressions

This Question is Closed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3take out the common factor what is GCF(greatest common factor ) ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3right take out 2 from 18n^2 8 or in other words divide both terms by common factor \[2(\frac{ 18n^2 }{ 2 }\frac{ 8 }{ 2 })\]

phi
 one year ago
Best ResponseYou've already chosen the best response.1you should always be on the look out for "difference of squares"

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1@phi I don't understand...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.39 and 4 are perfect square roots and the negative between both terms so you can apply the difference of squares \[\huge\rm a^2b^2 =(ab)(a+b)\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1so how would i implement it on 9^2  4?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3this is how i do it take square roots of both terms write in two parentheses (sqrt of 1st term `+` sqrt of 2nd term) (sqrt of 1st term `` sqrt of 2nd term ) lolol

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1okay.. so would it be (3+4)(34)?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3what about n it's 9n^2  4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3looks good don't forget the common factor 2(3n+4)(3n4)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3dw:1444163520807:dw take square root of both termz

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0\[9n^2  4 =(3n)^22^2\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1sorry but this is not clear to me at all

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i need more help on this

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3alright let's start when the coefficient of both terms are perfect squares and the exponent of the variable is even and the negative sign between the terms then you can use difference of squares hint

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not that good at math. I would try to help you but I would end up failing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no thats not true you wont fail.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and if you do like there is a saying First comes frailer second comes success.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\huge\rm x^2 4\] even power and both coefficient are perfect squares since the negative sign between them we can use the hint \[\huge\rm\color{ReD}{ a}^2 \color{blue}{b}^2 = (ab)(a+b)\] we have to rewrite 4 as 2 exponent so 2^2 = 4 \[\huge\rm \color{ReD}{x}^2\color{blue}{2}^2=(\color{Red}{x}\color{blue}{2}(\color{Red}{x}+\color{blue}{2}) \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that wuill take a while. lol.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3that's what zarkon mentioned above that's same as taking square roots of both terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3dw:1444164108305:dw one with negative sign and one with positive

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3now make sense or no ?? hm

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1u kinda do.. but i m still trying to understand it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3alright take ur time let me know what u don't understand :=) will try to explain

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1if we have 16^2  49, would we have (4  7)(4+7) or something else?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3there should be a variable

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3remember if it's 16^249 both are `like` terms so we can just combine them

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1oh okay... so would we have that as (4n + 7)(4n  7) ?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1so for my original problem the answer would be:

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1\[2(9n^2  4)\] \[9n^2  4 \implies (3n + 2)(3n2)\] \[\large Answer\] \[2(3n+2)(3n2)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\(\huge\color{Green}{\checkmark}\)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Thank you so much! I just want to review the steps...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3just do some example u will get the concept :=)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.11. Find the GCF of the terms 2. Put the GCF outside of the parenthesis. 3. Divide the terms of the question by the GCF. 4. (if there are perfect squares, then we use a^2  b^2 = (a + b)(a  b)

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.15. and then put the GCF outside

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3right for perfect squares: sign should be negative between terms both numbers should be perfect squares even power!

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i have a small question... if we have x^2, can we turn the x to be a positive ?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1...since the exponent is a positive, i thought that that's possible

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3it depends on 2nd term let's say we have \[\huge\rm x^2  9\] we can factor out the negative one \[\large\rm 1(x^2+9)\] now there is a positive sign we can't factor it out

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3and if we have \[\huge\rm x^2+9\] take out the negative one a should be positive

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1x^2 + y^3... i think this was a question on a test that i took

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1like we had to divide with exponents and that was in the denominator... wait. let me write it out \[\frac{ 1 }{ x^{2}y^3 }\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i moved x^{2} up to the numerator. \[\frac{ x^2 }{ y^3 } \implies \frac{ x^2 }{ y^3}\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1would that be valid?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3ohhh no wait why did you flip the fraction ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3IF IF `exponent ` is negative then you should flip the fraction

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1i only moved x^{2} since the exponent was negative

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3wait a sec its lagging let me refresh the page

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\huge\rm \frac{ 1 }{ x^2y^3}\] is this ur question ?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1no\[\huge \frac{ 1 }{ x^{2}y^3 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3right \[\huge\rm \frac{ 1 }{ x^{2}y^3 } = \frac{ x^2 }{ y^3 }\] sign would be at the top never leave the negative sign in the denominator negative times positive = negative

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3you forgot the negative sign variables are correct :=)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.