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mckenzieandjesus

  • one year ago

Find the first, fourth, and eighth terms of the sequence. A(n)=-5*2^n^-1 –5; –40; –640 –20; –160; –2,560 –10; –80; –1,280 1; –1,000; –10,000,000

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  1. mckenzieandjesus
    • one year ago
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    @Mehek14 can please u help?

  2. mckenzieandjesus
    • one year ago
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    @Loser66 can u help?

  3. mckenzieandjesus
    • one year ago
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    @jim_thompson5910

  4. mckenzieandjesus
    • one year ago
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    @hartnn can u please help?

  5. marigirl
    • one year ago
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    \[A(n)=5\times 2^{n-1}\] Is that how the equation is showing?

  6. mckenzieandjesus
    • one year ago
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    yes!

  7. marigirl
    • one year ago
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    So first term you would sub in n=1 \[A(n)= -5 \times 2^{n-1}\] \[A(1)= -5 \times 2^{1-1}\] \[A(1)= -5 \times 2^{0}\] \[A= -5 \times 1\] A=-5

  8. marigirl
    • one year ago
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    fourth sub in n=4 \[A= -5 \times 2^{4-1}\] \[A= -5 \times 2^{3}\] \[A= -5 \times 8\] A=-40

  9. marigirl
    • one year ago
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    try the eight term and see if you find the matching sequence from the answers :)

  10. mckenzieandjesus
    • one year ago
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    -640

  11. mckenzieandjesus
    • one year ago
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    |dw:1444169037463:dw|

  12. mckenzieandjesus
    • one year ago
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    Thank You so much. Could you help me with this one? Evaluate the function rule for the given value. f(x)=15^x for x=3

  13. mckenzieandjesus
    • one year ago
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    15^3=3375

  14. marigirl
    • one year ago
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    yes that looks good

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