mckenzieandjesus one year ago Find the first, fourth, and eighth terms of the sequence. A(n)=-5*2^n^-1 –5; –40; –640 –20; –160; –2,560 –10; –80; –1,280 1; –1,000; –10,000,000

1. mckenzieandjesus

2. mckenzieandjesus

@Loser66 can u help?

3. mckenzieandjesus

@jim_thompson5910

4. mckenzieandjesus

5. marigirl

$A(n)=5\times 2^{n-1}$ Is that how the equation is showing?

6. mckenzieandjesus

yes!

7. marigirl

So first term you would sub in n=1 $A(n)= -5 \times 2^{n-1}$ $A(1)= -5 \times 2^{1-1}$ $A(1)= -5 \times 2^{0}$ $A= -5 \times 1$ A=-5

8. marigirl

fourth sub in n=4 $A= -5 \times 2^{4-1}$ $A= -5 \times 2^{3}$ $A= -5 \times 8$ A=-40

9. marigirl

try the eight term and see if you find the matching sequence from the answers :)

10. mckenzieandjesus

-640

11. mckenzieandjesus

|dw:1444169037463:dw|

12. mckenzieandjesus

Thank You so much. Could you help me with this one? Evaluate the function rule for the given value. f(x)=15^x for x=3

13. mckenzieandjesus

15^3=3375

14. marigirl

yes that looks good