mckenzieandjesus
  • mckenzieandjesus
Find the first, fourth, and eighth terms of the sequence. A(n)=-5*2^n^-1 –5; –40; –640 –20; –160; –2,560 –10; –80; –1,280 1; –1,000; –10,000,000
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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mckenzieandjesus
  • mckenzieandjesus
@Mehek14 can please u help?
mckenzieandjesus
  • mckenzieandjesus
@Loser66 can u help?
mckenzieandjesus
  • mckenzieandjesus
@jim_thompson5910

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More answers

mckenzieandjesus
  • mckenzieandjesus
@hartnn can u please help?
marigirl
  • marigirl
\[A(n)=5\times 2^{n-1}\] Is that how the equation is showing?
mckenzieandjesus
  • mckenzieandjesus
yes!
marigirl
  • marigirl
So first term you would sub in n=1 \[A(n)= -5 \times 2^{n-1}\] \[A(1)= -5 \times 2^{1-1}\] \[A(1)= -5 \times 2^{0}\] \[A= -5 \times 1\] A=-5
marigirl
  • marigirl
fourth sub in n=4 \[A= -5 \times 2^{4-1}\] \[A= -5 \times 2^{3}\] \[A= -5 \times 8\] A=-40
marigirl
  • marigirl
try the eight term and see if you find the matching sequence from the answers :)
mckenzieandjesus
  • mckenzieandjesus
-640
mckenzieandjesus
  • mckenzieandjesus
|dw:1444169037463:dw|
mckenzieandjesus
  • mckenzieandjesus
Thank You so much. Could you help me with this one? Evaluate the function rule for the given value. f(x)=15^x for x=3
mckenzieandjesus
  • mckenzieandjesus
15^3=3375
marigirl
  • marigirl
yes that looks good

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