Find the first, fourth, and eighth terms of the sequence. A(n)=-5*2^n^-1 –5; –40; –640 –20; –160; –2,560 –10; –80; –1,280 1; –1,000; –10,000,000

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Find the first, fourth, and eighth terms of the sequence. A(n)=-5*2^n^-1 –5; –40; –640 –20; –160; –2,560 –10; –80; –1,280 1; –1,000; –10,000,000

Mathematics
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@Mehek14 can please u help?
@Loser66 can u help?

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Other answers:

@hartnn can u please help?
\[A(n)=5\times 2^{n-1}\] Is that how the equation is showing?
yes!
So first term you would sub in n=1 \[A(n)= -5 \times 2^{n-1}\] \[A(1)= -5 \times 2^{1-1}\] \[A(1)= -5 \times 2^{0}\] \[A= -5 \times 1\] A=-5
fourth sub in n=4 \[A= -5 \times 2^{4-1}\] \[A= -5 \times 2^{3}\] \[A= -5 \times 8\] A=-40
try the eight term and see if you find the matching sequence from the answers :)
-640
|dw:1444169037463:dw|
Thank You so much. Could you help me with this one? Evaluate the function rule for the given value. f(x)=15^x for x=3
15^3=3375
yes that looks good

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