factoring quadratic expression...

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factoring quadratic expression...

Mathematics
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\[\huge 12x^2 + 12x + 3\]
factor out a 3 first

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\[\large 3(4x^2 + 4x + 1) \]
Then you'll notice something about the resulting quadratic
hint: \[(a+b)^2 = a^2+2ab+b^2\]
i still don't understand
using my model, let\[\large a=2x\] and \[\large b=1\]
ok
can you please get to the point?
ok, then \[12x^2+12x+3 = 3(2x+1)^2\]
there are like 4+ ways to factor quadratic equation i like AC method where we find two numbers when we multiply them we should get product of AC (a=leading coefficient , C= constant ) and when we add them we should get middle term which is b \[\rm Ax^2+Bx+C\] a=leading coefficient b=middle term c-constant
|dw:1444168815625:dw| multiply A times C what two numbers you should multiply to get 4 and when you add them you should get 4
36: 1, 2, 3, 4, 6, 9, 12, 18, 36
first step)take out the GCF so 3( 4x^2+4x+1) is correct
\[3 \color{ReD}{(4x^2+4x+1)}\] now we factor the quadratic equation 4x^2+4x+1
how do we factor that?
how do you want to factor it ? you can use quadratic formula or AC method i posted above
ac
alright read my comments let me know if you have a question :=)
i multiplied 4 x 1 = 4 factors of 4: 1, 2, 4
4 times 1 = 4 now what two numbers add up to 4 and when u multiply them you should get 4
3(2x + 1)(2x + 1)
hmm well in this question AC=4 and b=4 so two numbers are 2 times 2 =4 2+2= 4 and bec leading isn't equal to one we should factor by grouping |dw:1444169462918:dw| keep the first and last term write both numbers in the middle
can you please how u got 2x+1 ?? :=)
explain*
|dw:1444169574708:dw|
perfect!!!
and then i carried down the 3
|dw:1444169772616:dw|
|dw:1444169756892:dw| forgot the positive sign
yes right
okay thanks!

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