hayhay12345
  • hayhay12345
what is an equation of the line in slope intercept form m=3 and the y intercept is (0,4)
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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hayhay12345
  • hayhay12345
y=4x+3 y=-3x+4 y=4x-3 y=3x+4
hayhay12345
  • hayhay12345
i think its the last one
candyme
  • candyme
The slope intercept form is y=mx+b. Since m is the slope, we can fill in y=3x+b We also know that b is the y part of the y intercept. SO the full equation is y=3x+4

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candyme
  • candyme
Great! You had it!
hayhay12345
  • hayhay12345
i got it right?! sweet
hayhay12345
  • hayhay12345
can u help me with another?
candyme
  • candyme
Sure!
hayhay12345
  • hayhay12345
im going to screen shot it
hayhay12345
  • hayhay12345
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candyme
  • candyme
This one will be much easier if you get the y all by itself on the left. So start by adding the x to both sides. -12y-5x+5x=5x+11 -12y=5x+11 Now you want to divide by 12\[y=-\frac{ 5 }{ 12 }x-\frac{ 11 }{ 12 }\]
candyme
  • candyme
So the slope is the number in front of the x \[-\frac{ 5 }{ 12 }\] And the y intercept is the number that has no variable\[-\frac{ 11 }{ 12 }\]
hayhay12345
  • hayhay12345
so it is the third one right?
candyme
  • candyme
That's right!
hayhay12345
  • hayhay12345
thanks!! do u miind checking a few more for me i am pretty sure they are right i just want to make sure.
candyme
  • candyme
Sure
hayhay12345
  • hayhay12345
hayhay12345
  • hayhay12345
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hayhay12345
  • hayhay12345
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hayhay12345
  • hayhay12345
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candyme
  • candyme
Ok, on the first one the picture cut off that last piece of the equation. Based on your slope the answer is either b or c, but you need that number on the right side of the equals sign to finish it
candyme
  • candyme
The second one you posted you are correct
hayhay12345
  • hayhay12345
for the first on it was x+2y=4
candyme
  • candyme
For this one there is no slope, so there won't be a number with the x. Vertical lines are always written as x=__. So this graph is x=2
candyme
  • candyme
\(\color{#0cbb34}{\text{Originally Posted by}}\) @hayhay12345 for the first on it was x+2y=4 \(\color{#0cbb34}{\text{End of Quote}}\) Ok, so when you divide by 2 you will have \[y=-\frac{ 1 }{ 2 }x+2\]
candyme
  • candyme
So on it your graph would be c because it hits the y axis at 2
hayhay12345
  • hayhay12345
ohhhh ok thank you!! can u take a look at these two?
hayhay12345
  • hayhay12345
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candyme
  • candyme
For the vertical line above, you always write the equation as x=__. Since it crosses the x axis at (2,0) you write x=2
hayhay12345
  • hayhay12345
i put the wrong one sorry
hayhay12345
  • hayhay12345
its this one
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candyme
  • candyme
Both of those are correct :)
hayhay12345
  • hayhay12345
sweet i hate to ask again but could u check like 4-5 more for me plz?
candyme
  • candyme
I can do that :)
hayhay12345
  • hayhay12345
hayhay12345
  • hayhay12345
thats for one of them
hayhay12345
  • hayhay12345
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hayhay12345
  • hayhay12345
i had b for 14 btw
hayhay12345
  • hayhay12345
candyme
  • candyme
For that first one it is going to be d because it makes it skinny and it isn't negative so it won't flip upside down
candyme
  • candyme
For 14 you are correct
candyme
  • candyme
Also letter b for the one after that, because the > means dashed line and shaded above
hayhay12345
  • hayhay12345
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hayhay12345
  • hayhay12345
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hayhay12345
  • hayhay12345
hayhay12345
  • hayhay12345
thats all other than what i need to finish working out
hayhay12345
  • hayhay12345
i just need those last one i posted checked before i finish the complete work
candyme
  • candyme
Sorry I froze up there for a few minutes. I'll look at these for you real quick
hayhay12345
  • hayhay12345
ok and its all cool i was working out some others ones
candyme
  • candyme
The first one should actually be d because you want the shading to be on the bottom area.
hayhay12345
  • hayhay12345
ohh ok
candyme
  • candyme
On the absolute value graph, you need to move that 4 over to the other side. That will make it y=|x+2|-4 so it is actually c
candyme
  • candyme
The one about DVDs was correct
hayhay12345
  • hayhay12345
@candyme can you check these for me?
hayhay12345
  • hayhay12345
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