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anonymous
 one year ago
c+66/c^2/1+4/c
anonymous
 one year ago
c+66/c^2/1+4/c

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you mind drawing out your question? Im not understanding which ones are fractions and which arent. Your lack of parenthesis makes it hard to differentiate that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444169246249:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First we need to find a common denominator in both the numerator and denominator. For the numerator, the LCD between \(1\) and \(c^2\) is \(c^2\). Let's multiply \(c^2\) to the top and bottom of \(\dfrac{c}{1}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We get : \[\frac{\dfrac{c^2}{c^2} \cdot c+\dfrac{64}{c^2}}{1+\dfrac{4}{c}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The numerator will then simplify to \[\frac{\dfrac{c^3 +64}{c^2}}{1+\dfrac{4}{c}}\] Are you with me so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great. Now let's find the LCD in the denominator. The LCD in the denominator between \(1\) and \(c\) will be \(c\), therefore we multiply \(c\) to both the numerator and denominator of 1. \[\frac{c}{c} \cdot 1 + \frac{4}{c}\] This becomes: \(\dfrac{c+4}{c}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We're going to take \(\dfrac{c+4}{c}\) and replace \(1+\dfrac{4}{c}\) with this simplification :) \[\frac{\dfrac{c^3+64}{c^2}}{\dfrac{c+4}{c}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When we're dividing 2 fractions, we're going to multiply by the reciprocal of the second fraction to the first fraction. It follows this simple rule: \(\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}} \iff \dfrac{a}{b} \cdot \dfrac{d}{c} \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Therefore: \[\frac{c^3+64}{c^2} \cdot \frac{c}{c+4}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We're going to cross cancel our like terms but if we take a look, \(c^3+64\) can be expanded since it is of the form \(a^3+b^3\). Do you follow?
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