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haleyelizabeth2017
 one year ago
Determine the equation of the horizontal asymptotes, if any, of the function.
f(x)=4/x^2+1)
haleyelizabeth2017
 one year ago
Determine the equation of the horizontal asymptotes, if any, of the function. f(x)=4/x^2+1)

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it's this right? \[\Large f(x) = \frac{4}{x^2+1}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1444170111505:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1rewrite 4 as 4*1 dw:1444170139532:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the 1 up top can be written as \(\Large x^0\) dw:1444170171324:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the largest exponent for the numerator is 0 so the degree of the numerator is 0 the largest exponent for the denominator is 2 so the degree of the denominator is 2 dw:1444170219440:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Rule: If the degree of the numerator is smaller than the degree of the denominator, then the horizontal asymptote is always the line `y = 0`. Basically the x axis

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the denominator grows far faster than the numerator so as x gets larger, f(x) approaches 0 dw:1444170311640:dw it never actually gets to 0 though

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Good rule to know.
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