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haleyelizabeth2017
 one year ago
Determine the equation of the horizontal asymptotes, if any, of the function.
f(x)=(2x+1)/(x+1)
haleyelizabeth2017
 one year ago
Determine the equation of the horizontal asymptotes, if any, of the function. f(x)=(2x+1)/(x+1)

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haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{ 2x+1 }{ x+1 }\]

Rizags
 one year ago
Best ResponseYou've already chosen the best response.0are you allowed to use limits?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure.

Rizags
 one year ago
Best ResponseYou've already chosen the best response.0what class is this for?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0PreCalculus

Rizags
 one year ago
Best ResponseYou've already chosen the best response.0ok then maybe some limits are allowed

Rizags
 one year ago
Best ResponseYou've already chosen the best response.0are you familiar with limits?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Nope. But...the book gives us two methods we can use. Solving for x in terms of y is one method, and divide the numerator and denominator by the highest power of x is the second.

Rizags
 one year ago
Best ResponseYou've already chosen the best response.0multiply the whole thing by \[\large \frac{\frac{1}{x}}{\frac{1}{x}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the numerator and denominator are both polynomials the degrees are the same (they are both of degree 1) the horizontal asymptotes is the ratio of the leading coefficients

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in your example it is \[y=\frac{2}{1}=2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it always works this way if the degrees are the same if they are not, then it is different

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Okay, sorry...was afk for a moment there

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if the degree of the denominator is larger, then it is \(y=0\) if the degree of the numerator is larger, then there is no horizontal asymptote

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Okay, good to know. Thank you
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