Determine the equation of the horizontal asymptotes, if any, of the function. g(x)=(x+3)/((x+1)(x-2))

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Determine the equation of the horizontal asymptotes, if any, of the function. g(x)=(x+3)/((x+1)(x-2))

Mathematics
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\[g(x)=\frac{ x+3 }{ (x+1)(x-2) }\]
Would the horizontal asymptote be y=0? Or...?
what is the degree of the numerator? degree of the denominator?

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yes
I expanded the denominator to get \(x^2-x-2\)
the degree of the denominator is larger than the degree of the numerator
the actual expansion doesn't matter. The key here is that we have x^2 as the first term, so we have a 2nd degree polynomial in the denominator
Okay
this is not a mystery. plug in say \(x=100\) (not a hysterically large number) and see that you get an answer very close to zero
Okay. Thank you both :)

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