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haleyelizabeth2017

  • one year ago

Determine the equation of the horizontal asymptotes, if any, of the function. g(x)=(x+3)/((x+1)(x-2))

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  1. haleyelizabeth2017
    • one year ago
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    \[g(x)=\frac{ x+3 }{ (x+1)(x-2) }\]

  2. haleyelizabeth2017
    • one year ago
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    Would the horizontal asymptote be y=0? Or...?

  3. jim_thompson5910
    • one year ago
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    what is the degree of the numerator? degree of the denominator?

  4. anonymous
    • one year ago
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    yes

  5. haleyelizabeth2017
    • one year ago
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    I expanded the denominator to get \(x^2-x-2\)

  6. anonymous
    • one year ago
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    the degree of the denominator is larger than the degree of the numerator

  7. jim_thompson5910
    • one year ago
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    the actual expansion doesn't matter. The key here is that we have x^2 as the first term, so we have a 2nd degree polynomial in the denominator

  8. haleyelizabeth2017
    • one year ago
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    Okay

  9. anonymous
    • one year ago
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    this is not a mystery. plug in say \(x=100\) (not a hysterically large number) and see that you get an answer very close to zero

  10. haleyelizabeth2017
    • one year ago
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    Okay. Thank you both :)

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