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anonymous
 one year ago
FACTOR 2x^2 + x  28 = 0
There should be 2 x's. I am stuck at 2(x^2+x14)=0
anonymous
 one year ago
FACTOR 2x^2 + x  28 = 0 There should be 2 x's. I am stuck at 2(x^2+x14)=0

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@haleyelizabeth2017 Lists steps

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Wait, it was originally \(2x^2+2x28?\)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1What you have is the simplest it can go.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Originally 2x^2+x28=0

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Okay, then what you have so far is not correct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh yea i made a mistake, i thought the GCF was 2 when it can't be

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what can be mult. to make 56 but added to make 1

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.17 and 4 multiply to get 28, okay? So then...if one side is (2x+/_)(x+/_) we can plug in those two numbers to try and see which works.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im guessing that another way to do it Eli?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1So...let's try (2x7)(x+4) first. We get \(2x^2+8x7x28\) which simplified, would work. So, (2x7)(x+4) is the correct.

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1correct answer* ^^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 2x7=0 is x=7/2 or 3 1/2

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Normally, it is left as an improper fraction, so x=7/2 is better. and x=4 is correct as well.

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1You could have also used the quadratic formula.

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1It is a lot easier. Or, even complete the square works too

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ b \pm \sqrt{b^24ac} }{ 2a }\] \[ax^2+bx+c=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, i got a question... the formula is ax^2+bx+c... i was told that you mult. a*c and the number that you get has to be mult. by x number and x number, but those two number must also be able to be added together to equal B... did that make sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is there an exception to this??

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1You don't have to do anything to the a b or c. just plug the coefficients into the quadratic formula and solve. Lets use your problem for example. We were given \[2x^2+x28\] A would be 2, b would be 1, and c would be 28.

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ (1) \pm \sqrt{(1)^24(2)(28)} }{ 2(2) }\]\[\frac{ 1 \pm \sqrt{1+224} }{ 4 }\]and so on

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Did that make sense?

Hero
 one year ago
Best ResponseYou've already chosen the best response.0@Beleaguer did you figure out What the two numbers are?

Hero
 one year ago
Best ResponseYou've already chosen the best response.0In other words, can you solve m+n =1 mn =56
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