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@haleyelizabeth2017 Lists steps

Wait, it was originally \(2x^2+2x-28?\)

What you have is the simplest it can go.

Originally 2x^2+x-28=0

Okay, then what you have so far is not correct.

oh yea i made a mistake, i thought the GCF was 2 when it can't be

what can be mult. to make -56 but added to make 1

im guessing that another way to do it Eli?

correct answer* ^^

so 2x-7=0 is x=7/2 or 3 1/2

and x=-4

Normally, it is left as an improper fraction, so x=7/2 is better. and x=-4 is correct as well.

You could have also used the quadratic formula.

It is a lot easier. Or, even complete the square works too

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] \[ax^2+bx+c=0\]

Is there an exception to this??

Huh?

\[\frac{ -(1) \pm \sqrt{(1)^2-4(2)(-28)} }{ 2(2) }\]\[\frac{ -1 \pm \sqrt{1+224} }{ 4 }\]and so on

Did that make sense?

@Beleaguer did you figure out What the two numbers are?

In other words, can you solve
m+n =1
mn =-56