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anonymous
 one year ago
Please help
Find a second degree polynomial function, f(x)=ax^2+bx+c where such that f(2)=8, f'(2)=3, and f''(2)=4
anonymous
 one year ago
Please help Find a second degree polynomial function, f(x)=ax^2+bx+c where such that f(2)=8, f'(2)=3, and f''(2)=4

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0hints: f(x) = ax^2 + bx + c f ' (x) = 2ax + b f '' (x) = 2a

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The a, b, and c are confusing me

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0Do you see how I got f ' (x) = 2ax + b and f '' (x) = 2a ??

sgadi
 one year ago
Best ResponseYou've already chosen the best response.1\[ f(x)=ax^2+bx+c\\ f'(x)=2ax+b\\ f''(x)=2a \] Given \[ f(2) = 8=4a+2b+c \\ f'(x) =3=4a+b\\ f''(x) =4=2a \Rightarrow a=2\\ \] Solving above equation, we can say: \[ a=2\\ 3 = 4\times 2+b \Rightarrow b=38=5 \\ 4 \times 2+2\times (5)+c=8 \Rightarrow c = 10 \] Therefore \[a =2 \\ b=5 \\ c= 10 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No direct answers please.

sgadi
 one year ago
Best ResponseYou've already chosen the best response.1Hi @ospreytriple , what do you mean by no direct answers?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hi @sgadi . I noticed that you solved the problem for the asker. OpenStudy's code of conduct states that helpers are not to provide answers to askers but to assist and guide them so that they may be able to solve the problems for themselves.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so where did you get the 4 from in f(2)=8?

sgadi
 one year ago
Best ResponseYou've already chosen the best response.1@ospreytriple , I understand now. I am sorry. Shall I delete the post?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey, I'm not a moderator. Just a heads up for future reference.

sgadi
 one year ago
Best ResponseYou've already chosen the best response.1@ospreytriple , Thank you. @Sasha.O , Did you get everything clear?
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