anisah.21a
  • anisah.21a
Find k(a^2+6) given k(x)=sqrt(x-6)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
ok
jdoe0001
  • jdoe0001
\(\bf k(a^2+6)?\)
anisah.21a
  • anisah.21a
yes

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More answers

anonymous
  • anonymous
|dw:1444175009862:dw|
anonymous
  • anonymous
do you see where this is going
anonymous
  • anonymous
sorry wait
anisah.21a
  • anisah.21a
sort of but not really?
anonymous
  • anonymous
|dw:1444175116780:dw|
anisah.21a
  • anisah.21a
what is that...?
anonymous
  • anonymous
a property for a^2 + 6
jdoe0001
  • jdoe0001
\(\bf k({\color{brown}{ x}})=\sqrt{{\color{brown}{ x}}-6}\qquad {\color{brown}{ x}}=a^2+6\qquad thus \\ \quad \\ k({\color{brown}{ a^2+6}})=\sqrt{{\color{brown}{ a^2\cancel{+6}}}\cancel{-6}}\implies k(a^2+6)=?\)
anisah.21a
  • anisah.21a
what the hell is that lol
anisah.21a
  • anisah.21a
you just gave me the what was originally stated
jdoe0001
  • jdoe0001
|dw:1444176190588:dw|
anisah.21a
  • anisah.21a
your answer is wrong when i submitted it
jdoe0001
  • jdoe0001
yes... anything wrong with that? :)
anisah.21a
  • anisah.21a
was*
jdoe0001
  • jdoe0001
well, what did you get for \(k(a^2+6)\) anyway?
anisah.21a
  • anisah.21a
it is supposed to be a sqrt of something
jdoe0001
  • jdoe0001
so it's, so.. what what the above give you then?
anisah.21a
  • anisah.21a
GIVEN K(X)=SQRTX-6 FIND K(a^2+6)
anisah.21a
  • anisah.21a
so you're basically plugging in a^2+6 into x in sqrt(x-6)
anisah.21a
  • anisah.21a
i am not sure how to go further than that
jdoe0001
  • jdoe0001
yeap, that's all that's being asked, yes
jdoe0001
  • jdoe0001
\(\bf k({\color{brown}{ x}})=\sqrt{{\color{brown}{ x}}-6}\qquad {\color{brown}{ x}}=a^2+6\qquad thus \\ \quad \\ k({\color{brown}{ a^2+6}})=\sqrt{{\color{brown}{ a^2\cancel{+6}}}\cancel{-6}}\implies k(a^2+6)=?\) looks simple enough
anisah.21a
  • anisah.21a
well it is wrong when i submitted it and i have 99 attempts thanks though..

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