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anisah.21a
 one year ago
Find k(a^2+6) given k(x)=sqrt(x6)
anisah.21a
 one year ago
Find k(a^2+6) given k(x)=sqrt(x6)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444175009862:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you see where this is going

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0sort of but not really?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444175116780:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a property for a^2 + 6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf k({\color{brown}{ x}})=\sqrt{{\color{brown}{ x}}6}\qquad {\color{brown}{ x}}=a^2+6\qquad thus \\ \quad \\ k({\color{brown}{ a^2+6}})=\sqrt{{\color{brown}{ a^2\cancel{+6}}}\cancel{6}}\implies k(a^2+6)=?\)

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0what the hell is that lol

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0you just gave me the what was originally stated

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444176190588:dw

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0your answer is wrong when i submitted it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes... anything wrong with that? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, what did you get for \(k(a^2+6)\) anyway?

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0it is supposed to be a sqrt of something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it's, so.. what what the above give you then?

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0GIVEN K(X)=SQRTX6 FIND K(a^2+6)

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0so you're basically plugging in a^2+6 into x in sqrt(x6)

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0i am not sure how to go further than that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap, that's all that's being asked, yes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf k({\color{brown}{ x}})=\sqrt{{\color{brown}{ x}}6}\qquad {\color{brown}{ x}}=a^2+6\qquad thus \\ \quad \\ k({\color{brown}{ a^2+6}})=\sqrt{{\color{brown}{ a^2\cancel{+6}}}\cancel{6}}\implies k(a^2+6)=?\) looks simple enough

anisah.21a
 one year ago
Best ResponseYou've already chosen the best response.0well it is wrong when i submitted it and i have 99 attempts thanks though..
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