anonymous
  • anonymous
3y-2 2y-1 _____ + ______ 4 8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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KendrickLamar2014
  • KendrickLamar2014
Still need help?
anonymous
  • anonymous
yeah
KendrickLamar2014
  • KendrickLamar2014
Ok lets see....

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More answers

candyme
  • candyme
\[\frac{ 3y-2 }{ 4 }-\frac{ 2y-1 }{ 8 }\] So you just want to combine these, correct?
anonymous
  • anonymous
yup
KendrickLamar2014
  • KendrickLamar2014
Step 1. Distribute = \[\frac{ 3 }{ 4 } y + \frac{ -1 }{ 2 } + \frac{ 1 }{ 4 } y + \frac{ -1 }{ 8 }\]
KendrickLamar2014
  • KendrickLamar2014
Step 2. Combine Like Terms: = \[( \frac{ 3 }{ 4 }y + \frac{ 1 }{ 4 } y) + (\frac{ -1 }{ 2 } + \frac{ -1 }{ 8 })\]
candyme
  • candyme
I will let @KendrickLamar2014 finish, then show you a way that may/may not make sense to you
anonymous
  • anonymous
ok @candyme
KendrickLamar2014
  • KendrickLamar2014
Which equals: \[y + \frac{ -5 }{ 8 }\] and thats your answer
anonymous
  • anonymous
@KendrickLamar2014 the answer key shows that it equals |dw:1444177170611:dw| 8y-5 _____ 8
candyme
  • candyme
So your book is doing it the way I did.\[2(\frac{ 3y-2 }{ 4 })+\frac{ 2y-1 }{ 8 }\] Distribute that 2\[\frac{ 6y-4 }{ 8 } +\frac{ 2y-1 }{ 8 }\] \[\frac{ 6y+2y-4-1 }{ 8 }\]\[\frac{ 8y-5 }{ 8 }\]
candyme
  • candyme
@KendrickLamar2014 took it a step further and simplified the 8y/8 part
candyme
  • candyme
I multiplied it by 2 in the beginning so I could place all of it on one fraction. I needed a common denominator
KendrickLamar2014
  • KendrickLamar2014
haha sorry about that @frebrezze
candyme
  • candyme
Technically when you get into higher maths you will have to do it his way, but unless it says to simplify all the way I usually leave it

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