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anonymous

  • one year ago

3y-2 2y-1 _____ + ______ 4 8

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  1. KendrickLamar2014
    • one year ago
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    Still need help?

  2. anonymous
    • one year ago
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    yeah

  3. KendrickLamar2014
    • one year ago
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    Ok lets see....

  4. candyme
    • one year ago
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    \[\frac{ 3y-2 }{ 4 }-\frac{ 2y-1 }{ 8 }\] So you just want to combine these, correct?

  5. anonymous
    • one year ago
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    yup

  6. KendrickLamar2014
    • one year ago
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    Step 1. Distribute = \[\frac{ 3 }{ 4 } y + \frac{ -1 }{ 2 } + \frac{ 1 }{ 4 } y + \frac{ -1 }{ 8 }\]

  7. KendrickLamar2014
    • one year ago
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    Step 2. Combine Like Terms: = \[( \frac{ 3 }{ 4 }y + \frac{ 1 }{ 4 } y) + (\frac{ -1 }{ 2 } + \frac{ -1 }{ 8 })\]

  8. candyme
    • one year ago
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    I will let @KendrickLamar2014 finish, then show you a way that may/may not make sense to you

  9. anonymous
    • one year ago
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    ok @candyme

  10. KendrickLamar2014
    • one year ago
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    Which equals: \[y + \frac{ -5 }{ 8 }\] and thats your answer

  11. anonymous
    • one year ago
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    @KendrickLamar2014 the answer key shows that it equals |dw:1444177170611:dw| 8y-5 _____ 8

  12. candyme
    • one year ago
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    So your book is doing it the way I did.\[2(\frac{ 3y-2 }{ 4 })+\frac{ 2y-1 }{ 8 }\] Distribute that 2\[\frac{ 6y-4 }{ 8 } +\frac{ 2y-1 }{ 8 }\] \[\frac{ 6y+2y-4-1 }{ 8 }\]\[\frac{ 8y-5 }{ 8 }\]

  13. candyme
    • one year ago
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    @KendrickLamar2014 took it a step further and simplified the 8y/8 part

  14. candyme
    • one year ago
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    I multiplied it by 2 in the beginning so I could place all of it on one fraction. I needed a common denominator

  15. KendrickLamar2014
    • one year ago
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    haha sorry about that @frebrezze

  16. candyme
    • one year ago
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    Technically when you get into higher maths you will have to do it his way, but unless it says to simplify all the way I usually leave it

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