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anonymous
 one year ago
How do you calculate new functions from old ones using table quantities (x, f(x), g(x), f'(x), g'(x))?
anonymous
 one year ago
How do you calculate new functions from old ones using table quantities (x, f(x), g(x), f'(x), g'(x))?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have a specific question? It might be easier to help you with more details.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes there's a table that goes along with it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes there's a table that goes along with it.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1@tigel__ post the screenshot of the full problem please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The third one's the easiest by a slight margin. \[\frac{f(2)}{g(2)+5}=\frac{23}{13+5}\] Do you see how I got that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The second one could come next. Recall that \((fg)(x)=f(x)g(x)\), so \[(fg)(4)=f(4)g(4)=97\times25\] For the other two, you'll need to take derivatives. By the product rule (for the fourth problem): \[(fg)'(2)=f'(2)g(2)+f(2)g'(2)=32\times13+23\times(10)\] By the chain rule (for the first one): \[h'(4)=\bigg(g(f)\bigg)'(4)=g'(f(4))f'(4)=g'(97)f'(4)=\cdots\] Does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No I'm confused. on the first one

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1@tigel__ the one where you put 9700 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1(fg)(x) = (f*g)(x) (fg)(x) = f(x)*g(x) (fg)(4) = f(4)*g(4) (fg)(4) = 97*25 (fg)(4) = 2425

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I got f(4) and g(4) from the table look in the f(x) row and column that starts with 4 to get f(4) similar for g(4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh im sorry! I meant the other one the one above it,

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1h(x) = g(f(x)) h ' (x) = g ' (f(x)) * f ' (x) ... chain rule h ' (4) = g ' (f(4)) * f ' (4) ... replace every x with 4 h ' (4) = g ' (97) * f ' (4) ... use the table h ' (4) = (390) * (80) ... use the table h ' (4) = 31,200

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1f(4) = 97 f ' (4) = 80 g ' (97) = 390
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