pokiedokie
  • pokiedokie
(please walk me through this!) Without graphing, classify each system of equations as independent, dependent, or inconsistent. Solve independent systems by graphing. 6x - 2y = 2 2 + 6x = y
Algebra
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
yolomcswagginsggg
  • yolomcswagginsggg
Let's solve for x. 6x−2y=2 Step 1: Add 2y to both sides. 6x−2y+2y=2+2y 6x=2y+2 Step 2: Divide both sides by 6. 6x 6 = 2y+2 6 x= 1 3 y+ 1 3 Answer: x= 1 3 y+ 1 3
yolomcswagginsggg
  • yolomcswagginsggg
thats for the first equation.
yolomcswagginsggg
  • yolomcswagginsggg
1/3 y+ 1/3

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yikes
pokiedokie
  • pokiedokie
oh.. thank you!! that was easier than i expected
yolomcswagginsggg
  • yolomcswagginsggg
lol
anonymous
  • anonymous
\[6x - 2y = 2 \\2 + 6x = y\] you can substitute \(2+6x\) for \(y\) in the first equation, since that is what it is you get \[6x-2(2+6x)=2\]
anonymous
  • anonymous
@pokiedokie it might seem easy but that answer is totally wrong
pokiedokie
  • pokiedokie
oh whoops...
anonymous
  • anonymous
you are solving a system of equations, i.e. where the lines intersect. you are not solving for x and y in one equation which is impossible
anonymous
  • anonymous
do you understand what i wrote above?
pokiedokie
  • pokiedokie
yes i do understand a bit of it
anonymous
  • anonymous
can you solve \[6x-2(2+6x)=2\] for \(x\)?
pokiedokie
  • pokiedokie
i think so, but i'm still a little confused on where to start in the equation. like as in, do i take care of the parentheses first like in PEMDAS
anonymous
  • anonymous
no it is not arithmetic, it is algebra first use the distributive law to get rid of the parentheses
pokiedokie
  • pokiedokie
OH, okay thats what i meant sorry, yikes... so i distributed, is this correct: 6x - 4 + 12x = 2
anonymous
  • anonymous
yes
anonymous
  • anonymous
now combine like terms on the left
anonymous
  • anonymous
oh sorry, no it is not right, but it is close
anonymous
  • anonymous
\[6x - 4 -12x = 2 \] is more like it
pokiedokie
  • pokiedokie
oh okay, give me a second to combine
pokiedokie
  • pokiedokie
sorry, i'm terrible at math but do you mean combining 6x with 12x or 4 and 2
anonymous
  • anonymous
i mean do \[6x-12x\]
pokiedokie
  • pokiedokie
im pretty sure the placement in what i put is wrong but it is x - 4-6x = 2
anonymous
  • anonymous
what is \(6-12\)?
pokiedokie
  • pokiedokie
-6
anonymous
  • anonymous
ok so \[6x-12x=-6x\] right?
yolomcswagginsggg
  • yolomcswagginsggg
:P
anonymous
  • anonymous
so you should have \[-6x-4=2\] add \(4\) next
pokiedokie
  • pokiedokie
-6x = 6??
pokiedokie
  • pokiedokie
and then i just divide
pokiedokie
  • pokiedokie
@satellite73 the answer is -1, correct?
anonymous
  • anonymous
yes
pokiedokie
  • pokiedokie
thank you so much, sorry for being a pain in the butt!!
anonymous
  • anonymous
no problem btw this makes it "consistent" the fact that you get an answer
pokiedokie
  • pokiedokie
noted, thank you very much!

Looking for something else?

Not the answer you are looking for? Search for more explanations.