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pokiedokie

  • one year ago

(please walk me through this!) Without graphing, classify each system of equations as independent, dependent, or inconsistent. Solve independent systems by graphing. 6x - 2y = 2 2 + 6x = y

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  1. yolomcswagginsggg
    • one year ago
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    Let's solve for x. 6x−2y=2 Step 1: Add 2y to both sides. 6x−2y+2y=2+2y 6x=2y+2 Step 2: Divide both sides by 6. 6x 6 = 2y+2 6 x= 1 3 y+ 1 3 Answer: x= 1 3 y+ 1 3

  2. yolomcswagginsggg
    • one year ago
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    thats for the first equation.

  3. yolomcswagginsggg
    • one year ago
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    1/3 y+ 1/3

  4. anonymous
    • one year ago
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    yikes

  5. PokieDokie
    • one year ago
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    oh.. thank you!! that was easier than i expected

  6. yolomcswagginsggg
    • one year ago
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    lol

  7. anonymous
    • one year ago
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    \[6x - 2y = 2 \\2 + 6x = y\] you can substitute \(2+6x\) for \(y\) in the first equation, since that is what it is you get \[6x-2(2+6x)=2\]

  8. anonymous
    • one year ago
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    @pokiedokie it might seem easy but that answer is totally wrong

  9. PokieDokie
    • one year ago
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    oh whoops...

  10. anonymous
    • one year ago
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    you are solving a system of equations, i.e. where the lines intersect. you are not solving for x and y in one equation which is impossible

  11. anonymous
    • one year ago
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    do you understand what i wrote above?

  12. PokieDokie
    • one year ago
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    yes i do understand a bit of it

  13. anonymous
    • one year ago
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    can you solve \[6x-2(2+6x)=2\] for \(x\)?

  14. PokieDokie
    • one year ago
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    i think so, but i'm still a little confused on where to start in the equation. like as in, do i take care of the parentheses first like in PEMDAS

  15. anonymous
    • one year ago
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    no it is not arithmetic, it is algebra first use the distributive law to get rid of the parentheses

  16. PokieDokie
    • one year ago
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    OH, okay thats what i meant sorry, yikes... so i distributed, is this correct: 6x - 4 + 12x = 2

  17. anonymous
    • one year ago
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    yes

  18. anonymous
    • one year ago
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    now combine like terms on the left

  19. anonymous
    • one year ago
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    oh sorry, no it is not right, but it is close

  20. anonymous
    • one year ago
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    \[6x - 4 -12x = 2 \] is more like it

  21. PokieDokie
    • one year ago
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    oh okay, give me a second to combine

  22. PokieDokie
    • one year ago
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    sorry, i'm terrible at math but do you mean combining 6x with 12x or 4 and 2

  23. anonymous
    • one year ago
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    i mean do \[6x-12x\]

  24. PokieDokie
    • one year ago
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    im pretty sure the placement in what i put is wrong but it is x - 4-6x = 2

  25. anonymous
    • one year ago
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    what is \(6-12\)?

  26. PokieDokie
    • one year ago
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    -6

  27. anonymous
    • one year ago
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    ok so \[6x-12x=-6x\] right?

  28. yolomcswagginsggg
    • one year ago
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    :P

  29. anonymous
    • one year ago
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    so you should have \[-6x-4=2\] add \(4\) next

  30. PokieDokie
    • one year ago
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    -6x = 6??

  31. PokieDokie
    • one year ago
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    and then i just divide

  32. PokieDokie
    • one year ago
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    @satellite73 the answer is -1, correct?

  33. anonymous
    • one year ago
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    yes

  34. PokieDokie
    • one year ago
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    thank you so much, sorry for being a pain in the butt!!

  35. anonymous
    • one year ago
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    no problem btw this makes it "consistent" the fact that you get an answer

  36. PokieDokie
    • one year ago
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    noted, thank you very much!

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