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meilendurcer
 one year ago
If m<EBF = 7y3 and m<FBC = 3y+3, find y so that
EBperpendicularBC. I got y= 1.5
meilendurcer
 one year ago
If m<EBF = 7y3 and m<FBC = 3y+3, find y so that EBperpendicularBC. I got y= 1.5

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PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1How did you arrive to that answer?

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1Remember that if EB is perpendicular to BC, then angle EBC is 90 degrees.

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1Hm. It says that angle EBF is 7y3 and angle FBC is 3y +3.

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1These two angles make up angle EBC

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1It isn't given that the two angles are congruent. If the value of the two angles were congruent, then this would work. But that info isnt given

meilendurcer
 one year ago
Best ResponseYou've already chosen the best response.0i know there's another way to put them but i forgot my notes

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1Its fine. You see that EBF AND FBC equal EBC, right?

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1Alright. And since the question tells us that assuming EBC is perpendicular, what is the value of y. So EBC=90. \[(7y3)+(3y+3)=90\]

meilendurcer
 one year ago
Best ResponseYou've already chosen the best response.0yeah that's the one

PhantomCrow
 one year ago
Best ResponseYou've already chosen the best response.1Alright. So now use algebra to solve for y and see what you get.
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