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meilendurcer

  • one year ago

If m<EBF = 7y-3 and m<FBC = 3y+3, find y so that EBperpendicularBC. I got y= -1.5

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  1. meilendurcer
    • one year ago
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  2. PhantomCrow
    • one year ago
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    How did you arrive to that answer?

  3. PhantomCrow
    • one year ago
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    Remember that if EB is perpendicular to BC, then angle EBC is 90 degrees.

  4. meilendurcer
    • one year ago
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    subtract 3y

  5. PhantomCrow
    • one year ago
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    From what?

  6. meilendurcer
    • one year ago
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    7y

  7. PhantomCrow
    • one year ago
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    Hm. It says that angle EBF is 7y-3 and angle FBC is 3y +3.

  8. meilendurcer
    • one year ago
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    \[7y-3=3y+3\]

  9. PhantomCrow
    • one year ago
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    These two angles make up angle EBC

  10. PhantomCrow
    • one year ago
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    It isn't given that the two angles are congruent. If the value of the two angles were congruent, then this would work. But that info isnt given

  11. meilendurcer
    • one year ago
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    i know there's another way to put them but i forgot my notes

  12. PhantomCrow
    • one year ago
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    Its fine. You see that EBF AND FBC equal EBC, right?

  13. meilendurcer
    • one year ago
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    yes

  14. PhantomCrow
    • one year ago
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    Alright. And since the question tells us that assuming EBC is perpendicular, what is the value of y. So EBC=90. \[(7y-3)+(3y+3)=90\]

  15. meilendurcer
    • one year ago
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    yeah that's the one

  16. PhantomCrow
    • one year ago
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    Alright. So now use algebra to solve for y and see what you get.

  17. meilendurcer
    • one year ago
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    y=9?

  18. PhantomCrow
    • one year ago
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    Yep.

  19. meilendurcer
    • one year ago
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    thanks

  20. PhantomCrow
    • one year ago
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    np

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