looks like some webassign business
set the denominator equal to zero and solve
i.e. solve \[x^2-4x=0\] 0 is one answer, there is another
is \[x^2-x^4\] factorable?
oops i made a typo yes \[x^2-x^4=0\]
it is definitely factorable since both terms have a common factor of \(x^2\)
\[is (x-x^2) factorable \]
factor out the common factor of \(x^2\)
now whatever you did
*not whatever you did
Ok, I got it. Just had a brain fart. Thanks!
yw on line class?
Online homework, but class is on school campus
your horizontal asymptote is right, it is \(y=-1\)
Yea, I didn't submit the new answers to the questions yet
I'll be here on openstudy until the next sunrise, still got tons of homework questions left.