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LynFran
 one year ago
Find the distance from (0,0) to the line 4x4y=9
LynFran
 one year ago
Find the distance from (0,0) to the line 4x4y=9

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LynFran
 one year ago
Best ResponseYou've already chosen the best response.1ok so i work this problem ..but keep getting a negative distance...can that be??

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0nope, distance is always positive

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1i know thats what bothers mee

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0probably be easier if you write the line as \[y=x\frac{9}{4}\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1but dont we have to use the normal/ perpendicular formula \[d=\frac{ Ax+By+C }{ \pm \sqrt{A^2+B^2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay not familiar with that what are x and y in that formula ?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1the point given (0,0)..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then this gotta be simple right?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1but i keep getting a negative distance

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{9}{\sqrt{4^2+4^2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the numerator should be the absolute value your formula has a silly \(\pm\) in it which just means make sure it is positive

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1so 1.5909 would be the distance??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[d=\frac{ Ax+By+C }{ \pm \sqrt{A^2+B^2} }\] should be \[d=\frac{ Ax_0+By_0+C }{ \sqrt{A^2+B^2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk are you supposed to give a decimal approximation, or the answer as a radical?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1ok i have another question Determine K so that the distance from the origin to the line y=km+9; p=6 will be stated

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1@sleepyhead314 .. wat do u think?

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1well for your new question, if you plug in what they gave into the equation... \[\frac{ 9 }{ \sqrt{k^2 + 1} } = 6\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1where did u get that equation frm..?

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1ehh? the equation you gave before...? \[\frac{ Ax + By + C}{ \sqrt{A^2 + B^2} }\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1o its the same so 9=C but what about A and B?

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1I just plugged in A = k B = 1 C = 9 x = 0 y = 0 because y = km + 9 > km + y = 9

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1ok so we now solve for K?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1\[9=6(\sqrt{K^2+1})\]\[\frac{ 3 }{ 2}=\sqrt{k^2+1}\]\[\frac{ 9 }{ 4 }=k^2+1\]\[\frac{ 5 }{ 4 }=K^2\]\[\frac{ \sqrt{5} }{ 2 }=k\]

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1that's what I got :)

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1ok is there a way to check if its correct though?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1like when we solve equation we can sub the value we find back into the equation to see that its correct..eg 4x+2y=0 so y=0 and x=0 4(0)+2(0)=0 like this...^^

sleepyhead314
 one year ago
Best ResponseYou've already chosen the best response.1I suppose you could plug in A = (sqrt(5)/2) B = 1 C = 9 x = 0 y = 0 and make sure you get 6 ?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1ok cool.. thanks to all
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