Assume that n = 13, and p = 3/9.
Find the probability of at least 3 successes and at least 3 failures.

- Pulsified333

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- Pulsified333

@Musicdude

- anonymous

ok

- Pulsified333

I've tried two different methods but neither worked

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## More answers

- anonymous

ok that is a binomial probability within a binomial probability i think. i need to think for this

- anonymous

hold up i might be wrong

- Pulsified333

ok

- anonymous

ok its binomial probability with parameters

- anonymous

have you seen this yet? or heard of it?

- Pulsified333

I dont think so

- anonymous

ok its a hard concept so let me see how i can explain it

- anonymous

wow im stumped... i cant explain it but do you have a ti-84 or higher?

- anonymous

i can show you haw to get the answer

- Pulsified333

um I don't because the professor doesn't allow calculators

- anonymous

O.O

- anonymous

omg

- anonymous

hes evil

- Pulsified333

imagine the test

- anonymous

im in stat 3 and we use computers

- anonymous

but we code our own calculations

- anonymous

ok thats tricky to do without a calculator

- anonymous

and i really dont have a pencil because im on my way home on the bus with my phone

- anonymous

nor paper

- Pulsified333

it's okay

- anonymous

sorry dude ask @ganeshie8 or @satellite73

- Pulsified333

I got the answer

- anonymous

ok cool how?

- Pulsified333

:D

- anonymous

i just want to see

- ganeshie8

I don't see how you can possibly do it with out using calculator
http://www.wolframalpha.com/input/?i=%5Csum%5Climits_%7Bk%3D3%7D%5E%7B10%7D+%28%2813+choose+k%29*%283%2F9%29%5Ek+*+%286%2F9%29%5E%2813-k%29%29

- anonymous

lol same

- Pulsified333

basically do the Bernoulli trials for each one from 3-13 for both and then multiple them together to get .8611

- anonymous

it would be 2 separate probabilities

- Pulsified333

yeah then multiply them together

- anonymous

i think it would be two different answers because it is 2 different events

- anonymous

because both cant exist together

- Pulsified333

No because it says 3 success "and" 3 failures. Which in Finite math means multiply

- anonymous

but then where are the 8 trails go? if there aren't success not faliure

- anonymous

thats the thing

- anonymous

thats whats tricky because it creates a parameter

- anonymous

i know the answer but its really complex to get to without a calculator

- anonymous

is you did use the Bernoulli trials you would use 3-10 because you have to account for the "at least 3 faliures"

- anonymous

you there?

- Pulsified333

yeah

- anonymous

im guessing it would be around .86 just because i know

- anonymous

and i used a calculator

- Pulsified333

yeah

- anonymous

is that around what you got??

- Pulsified333

yeah i got .8611

- anonymous

yeah thats it

- anonymous

did you use a calculator??

- anonymous

or long math??

- Pulsified333

yeah calculator

- anonymous

ok cool

- Pulsified333

on the test he said to leave it as the setup to find the answer as the answer

- anonymous

ok thats cool

- anonymous

so do you get it??

- Pulsified333

yeah

- anonymous

alright dude goodnight then

- Pulsified333

night

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