anonymous
  • anonymous
I need help with a question !!!! reply and ill give you the equation
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
candyme
  • candyme
Please post your equation and we'll see if we can work it out :)
anonymous
  • anonymous
\[\sum_{n=1}^{\infty} 1+3^{n}/2^{n}\]
anonymous
  • anonymous
determine whether the series is convergent or divergent if convergent find the sum

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

candyme
  • candyme
I'm not as confident as I would like to be in this type of problem. I'm going to let the others help you out :)
anonymous
  • anonymous
I believe the series is divergent. Simplifying gives us \[1+(\frac{ 3 }{ 2 })^n\] If we were to substitute n with infinity, we'd see that the terms would grow exponentially. \[\lim_{n \rightarrow \infty}1+(\frac{ 3 }{ 2 })^n=\infty\]
anonymous
  • anonymous
Does this make sense?
anonymous
  • anonymous
yes thank you
anonymous
  • anonymous
You are welcome :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.