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jackfrost33
 one year ago
help!!!
how do you find a cosine ratio?
jackfrost33
 one year ago
help!!! how do you find a cosine ratio?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444181898957:dw here is my example \[\cos(x)=\frac{4}{5}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but that not be what you mean a specific question would help

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0i just need to know how to find the angle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the angle or the cosine of the angle?

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0the cosine of an angle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you have the sides of a right triangle?

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0yeah hypotenuse is 2 long leg is sr of 3 and short leg is 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is the length of the "adjacent' side over the length of the hypotenuse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it kind of depends on which angle and how it is oriented

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know what i mean by "adjacent" ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444182288625:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in the above picture \[\cos(x)=\frac{a}{h}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444182390167:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if it looks like that, then \[\cos(x0=\frac{\sqrt3}{2}\] but it may not look like that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1444182488404:dw for this one \[\cos(x)=\frac{1}{2}\]

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0the problem i was given looked like this..dw:1444182458243:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok looks like the first one i drew

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0except my square root sign was more artful you have \[\cos(30^\circ)=\frac{adjacent}{hypontenuse}=\frac{\sqrt3}{2}\]

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0so i would just solve the equation then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw you also have \[\sin(x)=\frac{opposite}{hypotenuse}=\frac{1}{2}

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops \[\sin(x)=\frac{opposite}{hypotenuse}=\frac{1}{2} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is no equation to solve that is your answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer to \[\cos(30^\circ)\] is \[\frac{\sqrt3}{2}\]

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much really.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yw you got more, or is that it?

jackfrost33
 one year ago
Best ResponseYou've already chosen the best response.0yeah theres more like 20 more but i think i can get them.
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