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jackfrost33

  • one year ago

help!!! how do you find a cosine ratio?

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  1. anonymous
    • one year ago
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    you got an example?

  2. anonymous
    • one year ago
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    |dw:1444181898957:dw| here is my example \[\cos(x)=\frac{4}{5}\]

  3. anonymous
    • one year ago
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    but that not be what you mean a specific question would help

  4. jackfrost33
    • one year ago
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    i just need to know how to find the angle.

  5. anonymous
    • one year ago
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    the angle or the cosine of the angle?

  6. jackfrost33
    • one year ago
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    the cosine of an angle

  7. anonymous
    • one year ago
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    do you have the sides of a right triangle?

  8. jackfrost33
    • one year ago
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    yeah hypotenuse is 2 long leg is sr of 3 and short leg is 1

  9. jackfrost33
    • one year ago
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    sr is square root

  10. anonymous
    • one year ago
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    oh ok

  11. anonymous
    • one year ago
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    it is the length of the "adjacent' side over the length of the hypotenuse

  12. anonymous
    • one year ago
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    so it kind of depends on which angle and how it is oriented

  13. anonymous
    • one year ago
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    do you know what i mean by "adjacent" ?

  14. jackfrost33
    • one year ago
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    yes

  15. anonymous
    • one year ago
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    |dw:1444182288625:dw|

  16. anonymous
    • one year ago
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    so in the above picture \[\cos(x)=\frac{a}{h}\]

  17. anonymous
    • one year ago
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    |dw:1444182390167:dw|

  18. anonymous
    • one year ago
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    if it looks like that, then \[\cos(x0=\frac{\sqrt3}{2}\] but it may not look like that

  19. anonymous
    • one year ago
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    |dw:1444182488404:dw| for this one \[\cos(x)=\frac{1}{2}\]

  20. jackfrost33
    • one year ago
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    the problem i was given looked like this..|dw:1444182458243:dw|

  21. anonymous
    • one year ago
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    ok looks like the first one i drew

  22. jackfrost33
    • one year ago
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    yes

  23. anonymous
    • one year ago
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    except my square root sign was more artful you have \[\cos(30^\circ)=\frac{adjacent}{hypontenuse}=\frac{\sqrt3}{2}\]

  24. jackfrost33
    • one year ago
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    so i would just solve the equation then

  25. anonymous
    • one year ago
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    btw you also have \[\sin(x)=\frac{opposite}{hypotenuse}=\frac{1}{2}

  26. anonymous
    • one year ago
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    oops \[\sin(x)=\frac{opposite}{hypotenuse}=\frac{1}{2} \]

  27. anonymous
    • one year ago
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    there is no equation to solve that is your answer

  28. anonymous
    • one year ago
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    the answer to \[\cos(30^\circ)\] is \[\frac{\sqrt3}{2}\]

  29. jackfrost33
    • one year ago
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    thanks so much really.

  30. anonymous
    • one year ago
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    yw you got more, or is that it?

  31. jackfrost33
    • one year ago
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    yeah theres more like 20 more but i think i can get them.

  32. anonymous
    • one year ago
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    ok good luck!

  33. jackfrost33
    • one year ago
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    thx

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