## jackfrost33 one year ago help!!! how do you find a cosine ratio?

1. anonymous

you got an example?

2. anonymous

|dw:1444181898957:dw| here is my example $\cos(x)=\frac{4}{5}$

3. anonymous

but that not be what you mean a specific question would help

4. jackfrost33

i just need to know how to find the angle.

5. anonymous

the angle or the cosine of the angle?

6. jackfrost33

the cosine of an angle

7. anonymous

do you have the sides of a right triangle?

8. jackfrost33

yeah hypotenuse is 2 long leg is sr of 3 and short leg is 1

9. jackfrost33

sr is square root

10. anonymous

oh ok

11. anonymous

it is the length of the "adjacent' side over the length of the hypotenuse

12. anonymous

so it kind of depends on which angle and how it is oriented

13. anonymous

do you know what i mean by "adjacent" ?

14. jackfrost33

yes

15. anonymous

|dw:1444182288625:dw|

16. anonymous

so in the above picture $\cos(x)=\frac{a}{h}$

17. anonymous

|dw:1444182390167:dw|

18. anonymous

if it looks like that, then $\cos(x0=\frac{\sqrt3}{2}$ but it may not look like that

19. anonymous

|dw:1444182488404:dw| for this one $\cos(x)=\frac{1}{2}$

20. jackfrost33

the problem i was given looked like this..|dw:1444182458243:dw|

21. anonymous

ok looks like the first one i drew

22. jackfrost33

yes

23. anonymous

except my square root sign was more artful you have $\cos(30^\circ)=\frac{adjacent}{hypontenuse}=\frac{\sqrt3}{2}$

24. jackfrost33

so i would just solve the equation then

25. anonymous

btw you also have $\sin(x)=\frac{opposite}{hypotenuse}=\frac{1}{2} 26. anonymous oops \[\sin(x)=\frac{opposite}{hypotenuse}=\frac{1}{2}$

27. anonymous

28. anonymous

the answer to $\cos(30^\circ)$ is $\frac{\sqrt3}{2}$

29. jackfrost33

thanks so much really.

30. anonymous

yw you got more, or is that it?

31. jackfrost33

yeah theres more like 20 more but i think i can get them.

32. anonymous

ok good luck!

33. jackfrost33

thx