A community for students.
Here's the question you clicked on:
 0 viewing
tacotime
 one year ago
A 4.30 kg box is pushed 1.20 m with a 36 N force. What is the final speed of the box if the coefficient of kinetic friction is 0.30?
tacotime
 one year ago
A 4.30 kg box is pushed 1.20 m with a 36 N force. What is the final speed of the box if the coefficient of kinetic friction is 0.30?

This Question is Closed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0on your box are acting two forces, namely: the driving force F=20 N and the friction force: R=\mu*m*g=0.3*4.30*9.81=...N Now the work done by those forces has to be equal to the kinetic energy change, so we can write this equation: \[Fd  Rd = \frac{1}{2}m{v^2}\] where \(v\) is the requested final speed, and \(d\) is the distance traveled by your box, namely \(d=1.2 \: m\)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0of course, \(m\) is the mass of your box
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.