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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    Given (Line segment) AB, explain how to construct a square with sides of length AB.

  2. anonymous
    • one year ago
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    Can you help @Photon336

  3. anonymous
    • one year ago
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    No!! It just that question, I think it about construction like with a compass and protractor. But i have no idea how to do that!

  4. anonymous
    • one year ago
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    Oh. wait I see I would explain it by saying something like first you would take your compass and open it to the length of AB and then go through the steps right!

  5. Photon336
    • one year ago
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    you could use the protractor to measure out the line segment

  6. Directrix
    • one year ago
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    Protractors may not be used in classic Greek constructions - just a straighedge.

  7. anonymous
    • one year ago
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    right a straight edge but would that be right if you did that then you would explain the steps=)

  8. Directrix
    • one year ago
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    You cannot use any measuring device. Do you want me to show you a way to do the construction?

  9. anonymous
    • one year ago
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    yes please, I'm confused =(

  10. Directrix
    • one year ago
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    Start with a given segment AB. We do not know how many inches long it is. |dw:1444186643797:dw|

  11. anonymous
    • one year ago
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    Yes okay

  12. Directrix
    • one year ago
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    Next, draw a working line. On it, you will eventually mark off the length of segment AB.| dw:1444186761133:dw|

  13. anonymous
    • one year ago
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    how do you draw a working line?

  14. Directrix
    • one year ago
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    On the working line, locate a point (not an end point) and call it A. Draw a working line with the straightedge. No specific length. |dw:1444186886889:dw|

  15. anonymous
    • one year ago
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    ohh okay.

  16. Directrix
    • one year ago
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    Go to the given segment AB. Open the compass. Place the sticky foot on point A. Stretch the compass so that the sticky foot stays on A while you open the compass just far enough to place the pencil end of the compass on point B. The sticky foot and the pencil foot are now the length of AB apart.

  17. anonymous
    • one year ago
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    but isn't that a measuring tool? Because your telling how big the line is now?

  18. Directrix
    • one year ago
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    Now, go to the working line and place the sticky foot on the point A on the working line. Swing the compass (draw an arc) with the sticky foot on A and when you swing the compass and intersect the working line, call that point B. Yes, we are measuring in a sense but not with a ruler. At no time will we have any lengths in inches.

  19. Directrix
    • one year ago
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    |dw:1444187235335:dw|

  20. anonymous
    • one year ago
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    ohh okay go on..

  21. Directrix
    • one year ago
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    We will now make a right angle at A on the working line. Squares have right interior angles.

  22. anonymous
    • one year ago
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    yep squares have 4 right angles lol!

  23. anonymous
    • one year ago
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    do you accomplish this right angle with a protractor?

  24. Directrix
    • one year ago
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    Close the compass to about 1/3 the width it had. Then, put the sticky foot on A and swing to the right and left of A. Do the same thing at point B using the SAME compass width. |dw:1444187336567:dw|

  25. Directrix
    • one year ago
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    Open the compass a tiny bit more. Place the sticky foot on the point where the arc to the left of point A intersected the working line. From that point, swing an arc long enough to go above point A |dw:1444187611034:dw|

  26. Directrix
    • one year ago
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    Now, put the sticky foot on the intersection of the arc to the right of point A and swing the same arc. Take note of where the two arcs intersect. |dw:1444187691528:dw|

  27. Directrix
    • one year ago
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    >>do you accomplish this right angle with a protractor? NO, use a protractor at any point and the construction is incorrect. Put the protractor out of sight.

  28. anonymous
    • one year ago
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    yeah I figured that out once u showed u next reply lol

  29. Directrix
    • one year ago
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    The two arcs that were just drawn above point A - do the same for point B. |dw:1444187840266:dw|

  30. Directrix
    • one year ago
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    Two points determine a line. Use the straightedge to join point A to the point determined by the intersection of the 2 arcs above point A. |dw:1444187914876:dw|

  31. Directrix
    • one year ago
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    Do the same for B. |dw:1444187942531:dw|

  32. anonymous
    • one year ago
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    oh i get it would you do the same for the top by using the compass in the same way to reach the top segment?

  33. Directrix
    • one year ago
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    We have created right angles with vertices A and B. Now, get the measure of AB back on the compass.

  34. anonymous
    • one year ago
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    okay

  35. Directrix
    • one year ago
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    With the measure of AB on the compass, place the sticky foot on A and draw an arc above A that intersects the extended segment we just drew upwards from point A. |dw:1444188127641:dw|

  36. Directrix
    • one year ago
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    We clipped off length AB on that segment. Now, do the same for the extended segment from point B on the working line. |dw:1444188215585:dw|

  37. anonymous
    • one year ago
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    ohh then you would do the same for b and then you would use u straigh edge right?

  38. Directrix
    • one year ago
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    Yes. Last step coming up.

  39. Directrix
    • one year ago
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    Use the straightedge to join the 2 points where the last arcs we drew intersected the lines extending upwards from points A and B on the working line. |dw:1444188336677:dw|

  40. Directrix
    • one year ago
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    There is the constructed square with side AB. I named it square ABCD.

  41. anonymous
    • one year ago
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    thank you so much!! i understand now lol

  42. Directrix
    • one year ago
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    You are welcome.

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