Will medal and Fan!!!

- anonymous

Will medal and Fan!!!

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- chestercat

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- anonymous

Given (Line segment) AB, explain how to construct a square with sides of length AB.

- anonymous

Can you help @Photon336

- anonymous

No!! It just that question, I think it about construction like with a compass and protractor. But i have no idea how to do that!

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## More answers

- anonymous

Oh. wait I see I would explain it by saying something like first you would take your compass and open it to the length of AB and then go through the steps right!

- Photon336

you could use the protractor to measure out the line segment

- Directrix

Protractors may not be used in classic Greek constructions - just a straighedge.

- anonymous

right a straight edge but would that be right if you did that then you would explain the steps=)

- Directrix

You cannot use any measuring device. Do you want me to show you a way to do the construction?

- anonymous

yes please, I'm confused =(

- Directrix

Start with a given segment AB. We do not know how many inches long it is.
|dw:1444186643797:dw|

- anonymous

Yes okay

- Directrix

Next, draw a working line. On it, you will eventually mark off the length of segment AB.|
dw:1444186761133:dw|

- anonymous

how do you draw a working line?

- Directrix

On the working line, locate a point (not an end point) and call it A.
Draw a working line with the straightedge. No specific length.
|dw:1444186886889:dw|

- anonymous

ohh okay.

- Directrix

Go to the given segment AB. Open the compass. Place the sticky foot on point A.
Stretch the compass so that the sticky foot stays on A while you open the compass just far enough to place the pencil end of the compass on point B.
The sticky foot and the pencil foot are now the length of AB apart.

- anonymous

but isn't that a measuring tool? Because your telling how big the line is now?

- Directrix

Now, go to the working line and place the sticky foot on the point A on the working line.
Swing the compass (draw an arc) with the sticky foot on A and when you swing the compass and intersect the working line, call that point B.
Yes, we are measuring in a sense but not with a ruler. At no time will we have any lengths in inches.

- Directrix

|dw:1444187235335:dw|

- anonymous

ohh okay go on..

- Directrix

We will now make a right angle at A on the working line. Squares have right interior angles.

- anonymous

yep squares have 4 right angles lol!

- anonymous

do you accomplish this right angle with a protractor?

- Directrix

Close the compass to about 1/3 the width it had.
Then, put the sticky foot on A and swing to the right and left of A.
Do the same thing at point B using the SAME compass width.
|dw:1444187336567:dw|

- Directrix

Open the compass a tiny bit more.
Place the sticky foot on the point where the arc to the left of point A intersected the working line. From that point, swing an arc long enough to go above point A
|dw:1444187611034:dw|

- Directrix

Now, put the sticky foot on the intersection of the arc to the right of point A and swing the same arc. Take note of where the two arcs intersect.
|dw:1444187691528:dw|

- Directrix

>>do you accomplish this right angle with a protractor?
NO, use a protractor at any point and the construction is incorrect.
Put the protractor out of sight.

- anonymous

yeah I figured that out once u showed u next reply lol

- Directrix

The two arcs that were just drawn above point A - do the same for point B.
|dw:1444187840266:dw|

- Directrix

Two points determine a line. Use the straightedge to join point A to the point determined by the intersection of the 2 arcs above point A.
|dw:1444187914876:dw|

- Directrix

Do the same for B.
|dw:1444187942531:dw|

- anonymous

oh i get it would you do the same for the top by using the compass in the same way to reach the top segment?

- Directrix

We have created right angles with vertices A and B.
Now, get the measure of AB back on the compass.

- anonymous

okay

- Directrix

With the measure of AB on the compass, place the sticky foot on A and draw an arc above A that intersects the extended segment we just drew upwards from point A.
|dw:1444188127641:dw|

- Directrix

We clipped off length AB on that segment.
Now, do the same for the extended segment from point B on the working line.
|dw:1444188215585:dw|

- anonymous

ohh then you would do the same for b and then you would use u straigh edge right?

- Directrix

Yes.
Last step coming up.

- Directrix

Use the straightedge to join the 2 points where the last arcs we drew intersected the lines extending upwards from points A and B on the working line.
|dw:1444188336677:dw|

- Directrix

There is the constructed square with side AB. I named it square ABCD.

- anonymous

thank you so much!! i understand now lol

- Directrix

You are welcome.

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