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## anonymous one year ago How much tension must a rope withstand if it is used to accelerate a 1190.0 kg car vertically upward at 0.980 m/s2

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1. Michele_Laino

on you car are acting two forces: the weight force: $$W=m \cdot g= 1190 \cdot 9.81=...Newton$$ and the fictitious force: $$F=m \cdot a=1190 \cdot 0.980=... Newtom$$ so total force is $$W+F=...Newton$$

2. Michele_Laino

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