Zenmo
  • Zenmo
Help with factoring (2+h)^3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Zenmo
  • Zenmo
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]
Zenmo
  • Zenmo
\[(2+h)(4-2h^2+h^2)=8-4h+2h^2+4h-2h^2+h^3\] is what I get.
Zenmo
  • Zenmo
\[8+h^3\]

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Lauren32583
  • Lauren32583
Make sure that you put your answer in decending order like so h^3+6h^2+12h+8
Zenmo
  • Zenmo
How to get the answer?
Zenmo
  • Zenmo
I only get \[8+h^3\] when i factor out \[(2+h)(4-2h+h^2)\] from \[(2+h)\]
Zenmo
  • Zenmo
\[(2+h)^3\]
FireKat97
  • FireKat97
You shouldn't be using that rule, that rule is for \[a^3 + b^3 = (a + b) ( a^2 - ab + b^2)\]
Lauren32583
  • Lauren32583
you multiply (2+h) times itself 3 times bc it is cubed (2+h)(2+h)(2+h) *I distribute the first 2 then I distribute to the 3rd one. 4+ 2h+2h+h^2(2+h)
FireKat97
  • FireKat97
what you want to do is simplify \[(2 + h) (2 + h)^2\]
Lauren32583
  • Lauren32583
then all you do is distribute and combine like terms.
Zenmo
  • Zenmo
Oh, I got it now. Thanks all.

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